Question

Решить цепочку Cu-Cu(NO3)2-Cu(oh)2-CuSO4-(CuOH)2SO4

Answer 1

Cu + 4HNO3 = Cu(NO3)2+NO2+ 2H2
Сu(NO3)2+Ca(OH)2 = Cu(OH)2+Ca(NO3)2
Cu(OH)2+H2SO4 = CuSO4+2H2O
2CuSO4+2H2O = (CuOH)2SO4+H2SO4

Answer 2

Сu+HNO3 ->Cu(NO3)2+H2
Cu(NO3)2+NaOH -> Cu(OH)2+NaNO3
Cu(OH)2+FeSO4 -> CuSo4 +Fe(OH)2

Answer 3

Cu-Cu(NO3)2-Cu(OH)2-CuSO4-(CuOH)2SO4 Reaction

The given chemical reaction involves a series of transformations starting with copper (Cu) and ending with (CuOH)2SO4. Let's break down the reaction step by step:

1. Cu - This represents copper, which is the starting material.

2. Cu(NO3)2 - Copper(II) nitrate (Cu(NO3)2) is a compound formed by the reaction of copper with nitric acid. It consists of copper ions (Cu2+) and nitrate ions (NO3-).

3. Cu(OH)2 - When copper(II) nitrate reacts with sodium hydroxide (NaOH), it forms copper(II) hydroxide (Cu(OH)2) and sodium nitrate (NaNO3).

4. CuSO4 - Copper(II) hydroxide can further react with sulfuric acid (H2SO4) to produce copper(II) sulfate (CuSO4) and water (H2O).

5. (CuOH)2SO4 - The compound (CuOH)2SO4 is not directly mentioned in the search results. However, it is likely a combination of copper(II) hydroxide (Cu(OH)2) and sulfuric acid (H2SO4), resulting in the formation of a copper sulfate compound.

Please note that the specific reaction conditions, such as temperature and concentration, are not provided in the question. These conditions can affect the reaction outcomes.

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