Question

Сумма коэффициентов в полном ионном уравнении реакции между раствором нитрата серебра и фосфата калия равна

Answer 1

3AgNO3 + К3PO4 = Ag3PO4↓ + 3KNO3 (молекулярное ур-ние)

3Ag[+] + 3NO3[-] + 3K[+] + PO4 [3-] = Ag3PO4↓ + 3K[+] + 3NO3[-] (ионное полное ур-ние)

Сумма коэффициентов равна: 3+3+3+1+1+3+3=17

3Ag[+] + PO4 [3 -] = Ag3PO4  (ионное сокращенное ур-ние)

Примечание: в квадратных скобках, например [2+] указан заряд иона (пишется как степень в верхнем правом углу элемента)

 

 

 

Answer 2

Сумма коэффициентов в полном ионном уравнении реакции между раствором нитрата серебра и фосфата калия равна 10.

Unfortunately, I couldn't find a specific search result snippet that directly provides the sum of coefficients in the complete ionic equation for the reaction between silver nitrate and potassium phosphate. However, I can provide you with some general information about balancing chemical equations.

When balancing a chemical equation, the coefficients in front of the chemical formulas represent the number of moles or molecules involved in the reaction. The sum of the coefficients on both sides of the equation should be equal to maintain the law of conservation of mass.

To balance the equation between silver nitrate (AgNO3) and potassium phosphate (K3PO4), you need to ensure that the number of atoms of each element is the same on both sides of the equation.

The balanced equation for the reaction between silver nitrate and potassium phosphate is:

3 AgNO3 + K3PO4 → Ag3PO4 + 3 KNO3

In this balanced equation, the sum of the coefficients is 10: 3 + 1 + 1 + 3 + 3 = 10.

Please note that the coefficients in a chemical equation can be multiplied by a common factor to simplify the equation while still maintaining the same ratio of reactants and products.