Question

A) CuO → Cu → CuO → CuCl(2) b) Fe(2)O(3) → Fe →FeCl помогите))

Answer 1

Ответ смотри во вложении

Answer 2

Reaction A: CuO → Cu → CuO → CuCl2

The reaction you provided involves the transformation of copper oxide (CuO) into copper (Cu), then back into copper oxide (CuO), and finally into copper chloride (CuCl2).

The reaction can be broken down into the following steps:

1. CuO → Cu: In this step, copper oxide (CuO) is reduced to copper (Cu). The reaction can be represented as:

CuO → Cu [[1]](https://www.yaklass.ru/p/himija/8-klass/klassy-neorganicheskikh-veshchestv-14371/vzaimosviaz-mezhdu-klassami-neorganicheskikh-veshchestv-195050/re-d872a67a-1888-46ac-b92e-05018349cc45)

2. Cu → CuO: In this step, copper (Cu) is oxidized back into copper oxide (CuO). The reaction can be represented as:

Cu → CuO [[1]](https://www.yaklass.ru/p/himija/8-klass/klassy-neorganicheskikh-veshchestv-14371/vzaimosviaz-mezhdu-klassami-neorganicheskikh-veshchestv-195050/re-d872a67a-1888-46ac-b92e-05018349cc45)

3. CuO → CuCl2: In the final step, copper oxide (CuO) reacts with chlorine (Cl2) to form copper chloride (CuCl2). The reaction can be represented as:

CuO + Cl2 → CuCl2 Please note that the reaction you provided is not balanced, and the specific conditions (such as temperature, pressure, and presence of catalysts) may affect the reaction rate and outcome.

Reaction B: Fe2O3 → Fe → FeCl

The second reaction you provided involves the transformation of iron(III) oxide (Fe2O3) into iron (Fe), and then into iron chloride (FeCl).

The reaction can be broken down into the following steps:

1. Fe2O3 → Fe: In this step, iron(III) oxide (Fe2O3) is reduced to iron (Fe). The reaction can be represented as:

Fe2O3 → Fe 2. Fe → FeCl: In the second step, iron (Fe) reacts with chlorine (Cl2) to form iron chloride (FeCl). The reaction can be represented as:

Fe + Cl2 → FeCl Please note that the reaction you provided is not balanced, and the specific conditions (such as temperature, pressure, and presence of catalysts) may affect the reaction rate and outcome.

If you have any further questions or need clarification, feel free to ask!