Question

На аднауленне аксиду медзи (2) спатрэбиуся вадарод масай 1.00 г . Различыце масы медзи и вады якия утварылися пры гэтым Даю 15 баллов

Answer 1

Дано
m(H2)=1 g
CuO
----------------
m(Cu)-?
m(H2O)-?
CuO+H2-->Cu+H2O
M(H2)=2 g/mol
n(H2)=m/M=1/2=0.5mol
n(H2)=n(Cu) = n(H2O)
M(Cu)=64 g/mol
M(H2O)=18 g/mol
m(Cu)=n*M=0.5*64 = 32g
m(H2O)=n*M=0.5*18=9 g

ответ 32г , 9 г

Answer 2

I'm sorry, but I could not find any relevant results for your query. It seems like you are asking a chemistry question, but I'm not sure what language you are using. Could you please try to rephrase your question in English, French, or another language that I can understand? Thank you for your cooperation.Ответь+подробно.+На+аднауленне+аксиду+медзи+(2)+спатрэбиуся+вадарод+масай+1.00+г+.+Различыце+масы+медзи+и+вады+якия+утварылися+пры+гэтым++Даю+15+баллов