Question

1.Определите степени окисления элементов в следующих соединениях Cao, H2SO4, K3PO4, MnO2, H2S , Al(NO3)3, ZnSiO3, Na. 2. Составте формулы: 1) хлорида алюминия (с.о. +3) 2) Оксида магния 3)оксида калия срочно!!

Answer 1

1.
У кислорода везде степень окисления (-2), а у водорода (+1)
Ca(+2)O
H2S(+6)O4
K3(+1)P(+5)O4
Mn(+4)O2
H2S(-2)
Al(+3)(NO3)3(-1)  ( у азота степень окисления +3)
Zn(+2)Si(+4)O3
Na(0)
2.
AlCl3
MgO
K2O

Answer 2

Determining Oxidation States of Elements in Compounds

To determine the oxidation states of elements in compounds, we need to consider the known oxidation states of other elements and the overall charge of the compound. Here are the oxidation states of the elements in the given compounds:

1. CaO (Calcium oxide): - Calcium (Ca) is an alkaline earth metal, and its oxidation state is typically +2. - Oxygen (O) usually has an oxidation state of -2 in compounds. - Therefore, the oxidation state of Ca in CaO is +2, and the oxidation state of O is -2.

2. H2SO4 (Sulfuric acid