Question

Сколько литров газа образуется при сжигании 2 л диметиламина в 8.5 л кислорода и пропускания полученной смеси через избыток известковой воды?

Answer 1

Я бы немного условие изменил, чтобы было понятно. Но вот что у меня получилось: 

Answer 2

Calculation of Gas Produced

To calculate the amount of gas produced when burning 2 liters of dimethylamine in 8.5 liters of oxygen and passing the resulting mixture through an excess of slaked lime (calcium hydroxide), we need to determine the balanced chemical equation for the reaction.

The balanced chemical equation for the combustion of dimethylamine (C2H7N) is as follows:

C2H7N + 5O2 → 2CO2 + 4H2O + N2.

From the balanced equation, we can see that for every 1 mole of dimethylamine burned, 5 moles of oxygen are consumed, and 2 moles of carbon dioxide, 4 moles of water, and 1 mole of nitrogen gas are produced.

To find the amount of gas produced, we need to convert the given volumes of dimethylamine and oxygen into moles using the ideal gas law. The molar volume of an ideal gas at standard temperature and pressure (STP) is 22.4 liters/mol.

The number of moles of dimethylamine can be calculated as follows:

moles of dimethylamine = volume of dimethylamine / molar volume at STP.

Similarly, the number of moles of oxygen can be calculated as follows:

moles of oxygen = volume of oxygen / molar volume at STP.

Once we have the number of moles of dimethylamine and oxygen, we can use the balanced equation to determine the number of moles of gas produced.

Finally, we can convert the moles of gas produced back into liters using the molar volume at STP.

Let's perform the calculations:

Given: - Volume of dimethylamine = 2 liters - Volume of oxygen = 8.5 liters

Molar volume at STP = 22.4 liters/mol

1. Calculate the number of moles of dimethylamine: - moles of dimethylamine = 2 liters / 22.4 liters/mol = 0.0893 moles

2. Calculate the number of moles of oxygen: - moles of oxygen = 8.5 liters / 22.4 liters/mol = 0.3795 moles

3. Use the balanced equation to determine the number of moles of gas produced: - According to the balanced equation, for every 1 mole of dimethylamine burned, 1 mole of nitrogen gas is produced. - Therefore, the number of moles of nitrogen gas produced is equal to the number of moles of dimethylamine burned, which is 0.0893 moles.

4. Convert the moles of nitrogen gas produced back into liters: - volume of nitrogen gas = moles of nitrogen gas * molar volume at STP - volume of nitrogen gas = 0.0893 moles * 22.4 liters/mol = 1.9992 liters

Therefore, approximately 2 liters of gas (specifically nitrogen gas) are produced when burning 2 liters of dimethylamine in 8.5 liters of oxygen and passing the resulting mixture through an excess of slaked lime (calcium hydroxide).

Please note that this calculation assumes ideal conditions and may not account for all possible factors.