Question

1.какую массу сульфата калия и какой объем воды необходимо взять для приготовления 250 граммов 15 % раствора соли?

Answer 1

250*0.15=37.5 г соли
250-37.5=212.5 г воды или 212.5 мл

Answer 2

I searched the web for your question and found some results that might help you. Here is a summary of what I found:

- To prepare a 15% solution of potassium sulfate, you need to take the mass of the salt and the volume of water that satisfy the following formula: W = m р.в./m р-ра * 100 %, where W is the mass fraction of the salt, m р.в. is the mass of the salt, and m р-ра is the mass of the solution . - The mass of the solution is given as 250 g, so you can substitute this value and the mass fraction of 15% into the formula and solve for the mass of the salt: m р.в. = m р-ра * W/100 % = 250 * 15/100 % = 37.5 g . - To find the mass of water, you need to subtract the mass of the salt from the mass of the solution: m H2O = m р-ра - m р.в. = 250 - 37.5 = 212.5 g . - To find the volume of water, you need to use the density of water, which is 1 g/ml, and the formula: m = p * V, where m is the mass of water, p is the density of water, and V is the volume of water. You can rearrange the formula and solve for the volume of water: V = m/p = 212.5/1 = 212.5 ml.

I hope this answer is helpful for you. If you have any other questions, please feel free to ask me.