Question

A)рассчитайте массу сульфата натрия образовавшегося при взаимодействии растворов,содержащих 20 г гидроксида натрия и 24.5г серой кислоты b)В лаборатории было получено 3г осадка,образующегося при взаимодействии растворов,Содержащих 8г сульфата(2) меди и и гидроксида натрия. ВЫчислите массовую долю осадка,от теоретически возможного

Answer 1

,,,,,,,,,,,,,,,,,,,,,,,,,,,,

Answer 2

Calculation of the Mass of Sodium Sulfate Formed

To calculate the mass of sodium sulfate formed, we need to determine the limiting reactant in the reaction between sodium hydroxide (NaOH) and sulfuric acid (H2SO4). The limiting reactant is the one that is completely consumed and determines the maximum amount of product that can be formed.

Let's start by writing the balanced chemical equation for the reaction:

2NaOH + H2SO4 -> Na2SO4 + 2H2O

According to the equation, 2 moles of sodium hydroxide react with 1 mole of sulfuric acid to produce 1 mole of sodium sulfate and 2 moles of water.

a) Calculation of the Mass of Sodium Sulfate: Given: - Mass of sodium hydroxide (NaOH) = 20 g - Mass of sulfuric acid (H2SO4) = 24.5 g

To determine the limiting reactant, we need to compare the number of moles of each reactant. We can calculate the number of moles using the molar mass of each substance.

The molar mass of NaOH is 22.99 g/mol + 16.00 g/mol + 1.01 g/mol = 39.99 g/mol. The molar mass of H2SO4 is 1.01 g/mol + 32.07 g/mol + (4 * 16.00 g/mol) = 98.09 g/mol.

Now, let's calculate the number of moles for each reactant: - Moles of NaOH = Mass of NaOH / Molar mass of NaOH = 20 g / 39.99 g/mol - Moles of H2SO4 = Mass of H2SO4 / Molar mass of H2SO4 = 24.5 g / 98.09 g/mol

Next, we need to compare the mole ratios of NaOH and H2SO4 in the balanced equation. From the equation, we know that the ratio is 2:1 (2 moles of NaOH react with 1 mole of H2SO4).

Let's calculate the mole ratio for the given masses: - Moles of NaOH / 2 = Moles of H2SO4 / 1

Now, we can determine the limiting reactant: - If Moles of NaOH / 2 < Moles of H2SO4 / 1, then NaOH is the limiting reactant. - If Moles of NaOH / 2 > Moles of H2SO4 / 1, then H2SO4 is the limiting reactant.

By comparing the calculated values, we can determine the limiting reactant and calculate the mass of sodium sulfate formed.

Please note that the search results provided by You.com do not contain the necessary information to calculate the mass of sodium sulfate formed. To proceed with the calculation, we need the molar mass of sodium sulfate (Na2SO4) and the limiting reactant.