Question

1.Выпишите реакции нейтрализации и поставьте коэффициенты если необходимо. HCl + NaOH = NaCl + H2O HNO3 + Ca(OH)2 = Ca(NO3)2 +H2O 2H2O = 2H2 + O2 -571,6 кДж SO2 + H2O = H2SO3 NaOH + H3PO4 = Na3PO4 + H2O

Answer 1

HCL+NaOH=NaCL+H2O
2HNO3+Ca(OH)2=Ca(NO3)2+2H2O
3NaOH +H3PO4=Na3PO4+3H2O

Answer 2

Neutralization Reactions and Balanced Equations

Neutralization reactions occur when an acid reacts with a base to form a salt and water. The balanced equations for the given reactions are as follows:

1. HCl + NaOH → NaCl + H2O

In this reaction, one molecule of hydrochloric acid (HCl) reacts with one molecule of sodium hydroxide (NaOH) to produce one molecule of sodium chloride (NaCl) and one molecule of water (H2O).

2. HNO3 + Ca(OH)2 → Ca(NO3)2 + H2O

In this reaction, one molecule of nitric acid (HNO3) reacts with one molecule of calcium hydroxide (Ca(OH)2) to produce one molecule of calcium nitrate (Ca(NO3)2) and one molecule of water (H2O).

3. 2H2O → 2H2 + O2

In this reaction, two molecules of water (H2O) decompose to form two molecules of hydrogen gas (H2) and one molecule of oxygen gas (O2).

4. SO2 + H2O → H2SO3

In this reaction, one molecule of sulfur dioxide (SO2) reacts with one molecule of water (H2O) to produce one molecule of sulfurous acid (H2SO3).

5. NaOH + H3PO4 → Na3PO4 + H2O

In this reaction, one molecule of sodium hydroxide (NaOH) reacts with one molecule of phosphoric acid (H3PO4) to produce one molecule of sodium phosphate (Na3PO4) and one molecule of water (H2O).

Please note that the coefficients in the balanced equations represent the stoichiometric ratios of the reactants and products. These coefficients ensure that the number of atoms of each element is balanced on both sides of the equation.

I hope this helps! Let me know if you have any further questions.