Question

Напишите уравнения реакций с помощью которых можно осуществить превращения :1) CuO->Cu->CuO->CuCl22) Fe2O3->Fe->FeCl2Определите тип реакций

Answer 1

1) 2CuO =2 Cu+O2 разложение 

     2Cu+ O2= 2CuO соединение

      CuO+2HCl=CuCl2+H20 замещение

2)  2Fe2O3= 2Fe+3O2 разложение

      Fe+2HCl= FeCl2+H2 замещение

           

 

Answer 2

Conversion 1: CuO -> Cu -> CuO -> CuCl2

The given reaction involves the conversion of copper oxide (CuO) to copper (Cu), then back to copper oxide (CuO), and finally to copper chloride (CuCl2).

1. Conversion of CuO to Cu: - The reaction can be represented as: CuO + H2 → Cu + H2O. - This is a reduction reaction, where copper oxide is reduced to copper by hydrogen gas.

2. Conversion of Cu to CuO: - The reaction can be represented as: Cu + O2 → CuO. - This is an oxidation reaction, where copper is oxidized to copper oxide by oxygen gas.

3. Conversion of CuO to CuCl2: - The reaction can be represented as: CuO + 2HCl → CuCl2 + H2O. - This is a displacement reaction, where copper oxide reacts with hydrochloric acid to form copper chloride and water.

Conversion 2: Fe2O3 -> Fe -> FeCl2

The given reaction involves the conversion of iron(III) oxide (Fe2O3) to iron (Fe), and then to iron(II) chloride (FeCl2).

1. Conversion of Fe2O3 to Fe: - The reaction can be represented as: Fe2O3 + 3CO → 2Fe + 3CO2. - This is a reduction reaction, where iron(III) oxide is reduced to iron by carbon monoxide.

2. Conversion of Fe to FeCl2: - The reaction can be represented as: Fe + 2HCl → FeCl2 + H2. - This is a displacement reaction, where iron reacts with hydrochloric acid to form iron(II) chloride and hydrogen gas.

In summary, the reactions involved in the given transformations are reduction, oxidation, and displacement reactions.