Question

Смесь, состоящую из 1,48 г гидроксида калия и 6.6 г сульфата аммония нагрели до прекращения реакции. сколько литров аммиака при этом образовалось?

Answer 1

Прикрепил картинку с решением, если что не понятно - спрашивай, если есть ответ - лучше сверить) потому что под вечер голова совсем чего-то отказывается работать) но все должно быть верно 

Answer 2

Calculation of Ammonia Produced

To calculate the amount of ammonia produced when a mixture consisting of 1.48 g of potassium hydroxide (KOH) and 6.6 g of ammonium sulfate (NH4)2SO4 is heated until the reaction stops, we need to consider the balanced chemical equation for the reaction between these two compounds.

The balanced chemical equation for the reaction between potassium hydroxide and ammonium sulfate is as follows:

2 KOH + (NH4)2SO4 → 2 NH3 + K2SO4 + 2 H2O

From the balanced equation, we can see that 2 moles of KOH react with 1 mole of (NH4)2SO4 to produce 2 moles of NH3. Therefore, we need to convert the given masses of KOH and (NH4)2SO4 to moles and then use the stoichiometry of the balanced equation to determine the moles of NH3 produced.

1. Calculate the moles of KOH: - Molar mass of KOH = 39.10 g/mol (potassium: 39.10 g/mol, oxygen: 16.00 g/mol, hydrogen: 1.01 g/mol) - Moles of KOH = mass of KOH / molar mass of KOH = 1.48 g / 39.10 g/mol

2. Calculate the moles of (NH4)2SO4: - Molar mass of (NH4)2SO4 = 132.14 g/mol (nitrogen: 14.01 g/mol, hydrogen: 1.01 g/mol, sulfur: 32.07 g/mol, oxygen: 16.00 g/mol) - Moles of (NH4)2SO4 = mass of (NH4)2SO4 / molar mass of (NH4)2SO4 = 6.6 g / 132.14 g/mol

3. Determine the limiting reactant: - To determine the limiting reactant, compare the moles of KOH and (NH4)2SO4. The reactant that produces fewer moles of NH3 will be the limiting reactant. - Calculate the moles of NH3 that can be produced from each reactant using the stoichiometry of the balanced equation.

- Moles of NH3 from KOH = moles of KOH × (2 moles of NH3 / 2 moles of KOH) - Moles of NH3 from (NH4)2SO4 = moles of (NH4)2SO4 × (2 moles of NH3 / 1 mole of (NH4)2SO4)

- Compare the moles of NH3 produced from each reactant. The reactant that produces fewer moles of NH3 is the limiting reactant.

4. Calculate the moles of NH3 produced: - The moles of NH3 produced will be equal to the moles of NH3 from the limiting reactant.

5. Convert moles of NH3 to liters: - To convert moles of NH3 to liters, we need to use the ideal gas law equation: PV = nRT, where P is the pressure, V is the volume, n is the number of moles, R is the ideal gas constant, and T is the temperature. - Since the pressure, volume, and temperature are not provided in the question, we cannot calculate the volume of ammonia produced.

Therefore, without the information about the pressure, volume, and temperature, we cannot determine the volume of ammonia produced.