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Calculating the Mass of the Product of the Reaction between Aluminum and Sulfur
To calculate the mass of the product of the reaction between aluminum and sulfur, we first need to determine the chemical equation for the reaction. Once we have the balanced chemical equation, we can use stoichiometry to find the mass of the product.
Balanced Chemical Equation
The reaction between aluminum and sulfur forms aluminum sulfide. The balanced chemical equation for this reaction is:2 Al + 3 S → Al2S3
Using Stoichiometry to Calculate the Mass of the Product
To calculate the mass of the product, we can use the molar masses of aluminum and sulfur, as well as the stoichiometry of the reaction.- The molar mass of aluminum (Al) is approximately 26.98 g/mol. - The molar mass of sulfur (S) is approximately 32.07 g/mol.
From the balanced chemical equation, we can see that 2 moles of aluminum react with 3 moles of sulfur to produce 1 mole of aluminum sulfide (Al2S3).
Given that the mass of sulfur is 16 g, we can calculate the amount of sulfur in moles using its molar mass:
Number of moles of sulfur = Mass of sulfur / Molar mass of sulfur Number of moles of sulfur = 16 g / 32.07 g/mol
Now that we have the number of moles of sulfur, we can use the stoichiometry of the reaction to find the moles of aluminum and then the mass of aluminum sulfide produced.
Calculating the Mass of Aluminum Sulfide
Using the stoichiometry of the reaction, we find that for every 3 moles of sulfur, we need 2 moles of aluminum. Therefore, the number of moles of aluminum can be calculated as:Number of moles of aluminum = (3/2) * Number of moles of sulfur
Finally, we can calculate the mass of aluminum sulfide produced using the molar mass of aluminum sulfide, which is approximately 150.16 g/mol.
Mass of aluminum sulfide = Number of moles of aluminum sulfide * Molar mass of aluminum sulfide
By following these steps, you can calculate the mass of the product formed in the reaction between aluminum and sulfur.


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