Question

Определить обьем хлора, необходимый для взаимодействия его с 0,4 моль водорода, если при при этом образовался хлороводород.

Answer 1

Дано:

n(H2) = 0,4 моль

Найти:

V(Cl2)

Решение:

Вычислим объем выделившегося триоксида серы:

0,4 моль  х л

H2     +     Cl2  =  2HCl

1 моль    22,4 л

0,4 моль   ---  х л

1 моль  ---  22,4 л        

х = 0,4 моль ∙ 22,4 л \1 моль = 8,96 л

Ответ:  V(Cl2) = 8,96 л;

Answer 2

Calculating the Volume of Chlorine Gas Required

To determine the volume of chlorine gas required for the reaction with 0.4 moles of hydrogen to produce hydrogen chloride, we can use the balanced chemical equation for the reaction between chlorine and hydrogen:

Cl2 + H2 → 2HCl

According to the stoichiometry of the balanced chemical equation, 1 mole of chlorine reacts with 1 mole of hydrogen to produce 2 moles of hydrogen chloride.

Given that the reaction involves 0.4 moles of hydrogen, we can calculate the volume of chlorine gas required using the ideal gas law equation:

PV = nRT

Where: - P = pressure (assumed to be constant) - V = volume of the gas - n = number of moles of the gas - R = ideal gas constant - T = temperature (assumed to be constant)

Using the molar volume of an ideal gas at standard temperature and pressure (STP), which is 22.4 L/mol, we can calculate the volume of chlorine gas required.

Calculation

The number of moles of chlorine required can be calculated using the stoichiometry of the reaction:

0.4 moles of H2 → 0.4 moles of Cl2

Since 1 mole of any gas at STP occupies 22.4 L, the volume of chlorine gas required can be calculated as follows:

0.4 moles of Cl2 × 22.4 L/mole = 8.96 L

Therefore, the volume of chlorine gas required for the reaction with 0.4 moles of hydrogen to produce hydrogen chloride is 8.96 liters.