Question

При пиролизе октан разлагается на этилен и водород. Чему равен общий объём газов, образовавшихся при полном разложении 30 литров паров октана? Объёмы газов измерены при одинаковых условиях.

Answer 1

Уравнение пиролиза:
С8Н18=4С2Н4+Н2
Согласно закону Авогадро и стехиометрии и реакции из 30 литров октана образуется в 5 раз больший объем газообразных продуктов, т.е 30*5=150 л

Answer 2

Calculation of the Total Volume of Gases Produced from the Complete Decomposition of Octane

To calculate the total volume of gases produced from the complete decomposition of 30 liters of octane, we need to determine the molar ratio between octane, ethylene, and hydrogen.

According to the information provided, octane decomposes into ethylene and hydrogen during pyrolysis. However, the exact molar ratio is not specified. To proceed with the calculation, we will assume a balanced chemical equation for the decomposition of octane:

C8H18 → C2H4 + 4H2

Based on this equation, for every 1 mole of octane, we obtain 1 mole of ethylene and 4 moles of hydrogen.

To find the total volume of gases produced, we need to convert the given volume of octane vapor (30 liters) into moles. Since the volume of gases is measured under the same conditions, we can assume that the ideal gas law applies.

Using the ideal gas law equation: PV = nRT, where: - P is the pressure (assumed constant) - V is the volume - n is the number of moles - R is the ideal gas constant - T is the temperature (assumed constant)

Since the pressure and temperature are assumed to be constant, we can simplify the equation to: V = nR.

To convert the volume of octane vapor to moles, we need to know the molar volume of octane. However, this information is not provided in the search results. Therefore, we cannot accurately determine the total volume of gases produced without additional information.

Please provide the molar volume of octane, or any other relevant information, to proceed with the calculation.