Question

Преобразуйте данные схемы в уравнения реакций, составьте схемы электронного баланса: NH3+O2->N2+H2O Cu+HNO3(разб.)->Cu(NO3)+NO^+H2O

Answer 1

4NH3 +3O2 = 2N2 + 6H2O
2N(-3) - 6e = N2(0) восстановитель
O2(0) + 4e = 2O(-2) окислитель
Общий коэффициент равен 12: 4N(-3) + 3O2 = 2N2 + 6O(-2)

Cu + 4HNO3(разб.) = Cu(NO3)2 + 2NO2 + 2H2O
Cu(0) - 2e = Cu(+2) восстановитель
N(+5) + 1e = N(+4) окислитель
Cu + 2N(+5) = Cu(+2) + 2N(+4)

Answer 2

Conversion of Chemical Equations to Balanced Equations

To convert the given chemical equations into balanced equations, we need to ensure that the number of atoms of each element is the same on both sides of the equation. Let's break down each equation and balance them individually.

1. NH3 + O2 -> N2 + H2O

To balance this equation, we need to ensure that the number of nitrogen (N) and hydrogen (H) atoms is the same on both sides.

Let's start by balancing the nitrogen atoms. There are 2 nitrogen atoms on the right side (N2), so we need to have 2 nitrogen atoms on the left side as well. We can achieve this by placing a coefficient of 2 in front of NH3:

2 NH3 + O2 -> N2 + H2O

Next, let's balance the hydrogen atoms. There are 6 hydrogen atoms on the right side (H2O), so we need to have 6 hydrogen atoms on the left side as well. We can achieve this by placing a coefficient of 3 in front of H2O:

2 NH3 + O2 -> N2 + 3 H2O

Now, let's check the oxygen atoms. There are 5 oxygen atoms on the right side (3 H2O + O2), so we need to have 5 oxygen atoms on the left side as well. We can achieve this by placing a coefficient of 5/2 (or 2.5) in front of O2:

2 NH3 + 2.5 O2 -> N2 + 3 H2O

However, it is not ideal to have fractional coefficients in a balanced equation. To eliminate the fractional coefficient, we can multiply the entire equation by 2:

4 NH3 + 5 O2 -> 2 N2 + 6 H2O

Therefore, the balanced equation for the reaction NH3 + O2 -> N2 + H2O is:

4 NH3 + 5 O2 -> 2 N2 + 6 H2O

2. Cu + HNO3(разб.) -> Cu(NO3) + NO + H2O

To balance this equation, we need to ensure that the number of copper (Cu), nitrogen (N), hydrogen (H), and oxygen (O) atoms is the same on both sides.

Let's start by balancing the copper atoms. There is 1 copper atom on the left side (Cu), so we need to have 1 copper atom on the right side as well. We can achieve this by placing a coefficient of 1 in front of Cu(NO3):

Cu + HNO3(разб.) -> 1 Cu(NO3) + NO + H2O

Next, let's balance the nitrogen atoms. There is 1 nitrogen atom on the right side (NO), so we need to have 1 nitrogen atom on the left side as well. We can achieve this by placing a coefficient of 1 in front of HNO3:

Cu + 1 HNO3(разб.) -> 1 Cu(NO3) + NO + H2O

Now, let's balance the hydrogen atoms. There are 3 hydrogen atoms on the right side (HNO3 + H2O), so we need to have 3 hydrogen atoms on the left side as well. We can achieve this by placing a coefficient of 3 in front of H2O:

Cu + 1 HNO3(разб.) -> 1 Cu(NO3) + NO + 3 H2O

Finally, let's balance the oxygen atoms. There are 6 oxygen atoms on the right side (1 Cu(NO3) + NO + 3 H2O), so we need to have 6 oxygen atoms on the left side as well. We can achieve this by placing a coefficient of 2 in front of HNO3:

Cu + 2 HNO3(разб.) -> 1 Cu(NO3) + NO + 3 H2O

Therefore, the balanced equation for the reaction Cu + HNO3(разб.) -> Cu(NO3) + NO + H2O is:

Cu + 2 HNO3(разб.) -> 1 Cu(NO3) + NO + 3 H2O