Question

вычислить массу оксида меди 2 образовавшегося при 49 граммах гидроксида меди 2

Answer 1

0,5 моль    х моль

Cu(OH)2 = CuO + H2O

1 моль       1 моль

n = m/M

M(Cu(OH)2) = 64 + 16*2 + 1*2 = 98 г/моль

n(Cu(OH)2) = 49 г/ 98 г/моль = 0,5 моль

n(Cu(OH)2) = n(CuO) = 0,5 моль

m = n*M

M(CuO) = 64 + 16 = 80 г/моль

m(CuO) = 80 г/моль * 0,5 моль= 40 г

Ответ: 40 г

Answer 2

Calculating the Mass of Copper(II) Oxide (CuO)

To calculate the mass of copper(II) oxide (CuO) formed from 49 grams of copper(II) hydroxide (Cu(OH)2), we can use the chemical equation for the reaction between copper(II) hydroxide and heat to form copper(II) oxide and water.

The balanced chemical equation for the reaction is: 2Cu(OH)2(s) → 2CuO(s) + 2H2O(g)

Using this equation, we can calculate the mass of copper(II) oxide formed.

Calculation:

Given: Mass of copper(II) hydroxide (Cu(OH)2) = 49 grams

From the balanced chemical equation, the molar ratio of Cu(OH)2 to CuO is 2:2, which simplifies to 1:1.

This means that the molar mass of Cu(OH)2 is equal to the molar mass of CuO.

Using the molar mass of Cu(OH)2: Molar mass of Cu(OH)2 = 97 g/mol (from source

Therefore, the molar mass of CuO is also 97 g/mol.

Now, we can calculate the moles of Cu(OH)2: Moles of Cu(OH)2 = Mass of Cu(OH)2 / Molar mass of Cu(OH)2 Moles of Cu(OH)2 = 49 g / 97 g/mol Moles of Cu(OH)2 ≈ 0.505 moles

Since the molar ratio of Cu(OH)2 to CuO is 1:1, the moles of CuO formed will also be approximately 0.505 moles.

Finally, we can calculate the mass of CuO formed: Mass of CuO = Moles of CuO × Molar mass of CuO Mass of CuO = 0.505 moles × 97 g/mol Mass of CuO ≈ 48.8 grams

Therefore, the mass of copper(II) oxide formed from 49 grams of copper(II) hydroxide is approximately 48.8 grams.

I hope this helps! If you have any further questions, feel free to ask.