Question

Расставьте коэффициенты,преобразовав схемы в уравнения реакций и определите типы реакций Na+H2O=NaOH+H2 Na+NH3=NaNH2+H2

Answer 1

Смотрите фото во вложении 

Answer 2

2KClO3=2KCl+3O2-распада
3HgCl2+2Аl=2AlCl3+3Нg-замещения
3Н2О+В2О3=2Н3ВО3-совмещения
6HСl+2Al=2AlCl3+3H2-замещения
ПОБЛАГОДАРИ МЕНЯ!!!!

Answer 3

Equation 1: Na + H2O = NaOH + H2

To determine the coefficients and types of reactions for the given equation, let's break it down step by step.

Step 1: Write the unbalanced equation: Na + H2O = NaOH + H2

Step 2: Balance the equation by adjusting the coefficients: 2 Na + 2 H2O = 2 NaOH + H2

The balanced equation for the reaction is: 2 Na + 2 H2O = 2 NaOH + H2

The type of reaction is a single displacement reaction because sodium (Na) displaces hydrogen (H) from water (H2O) to form sodium hydroxide (NaOH) and hydrogen gas (H2).

Equation 2: Na + NH3 = NaNH2 + H2

Step 1: Write the unbalanced equation: Na + NH3 = NaNH2 + H2

Step 2: Balance the equation by adjusting the coefficients: 2 Na + 2 NH3 = 2 NaNH2 + H2

The balanced equation for the reaction is: 2 Na + 2 NH3 = 2 NaNH2 + H2

The type of reaction is also a single displacement reaction because sodium (Na) displaces hydrogen (H) from ammonia (NH3) to form sodium amide (NaNH2) and hydrogen gas (H2).

Please let me know if there is anything else I can help you with!