Question

Определите,с каким из указанных веществ будет реагировать гидроксид калия и напишите уравнения реакций,определив их тип: 1.Оксид алюминия 2.Хлорид меди 2 3.Гидроксид магния 4.Оксид серы 6 5.Сульфат железа 3

Answer 1

2KOH + Al2O3 +3H2O-> 2K[Al(OH)4]
2KOH + CuCl2 -> Cu(OH)2 +2KCl
2KOH + SO3 -> K2SO4 + H2O
6KOH + Fe2(SO4)3 -> 3K2SO4 + 2Fe(OH)3

Answer 2

2KOH + Al2O3 +3H2O = 2K[Al(OH)4] 
2KOH + CuCl2 = Cu(OH)2↓ +2KCl
2KOH + SO3 = K2SO4 + H2O
6KOH + Fe2(SO4)3 = 3K2SO4 + 2Fe(OH)3↓

Answer 3

Determining the Reactivity of Potassium Hydroxide with the Listed Substances

To determine the reactivity of potassium hydroxide with the listed substances, we will examine the potential reactions with each substance and identify the type of reaction involved.

1. Aluminum Oxide - Potassium hydroxide will react with aluminum oxide to form potassium aluminate. - The balanced chemical equation for this reaction is: ``` 2KOH + Al2O3 → 2KAlO2 + H2O ``` - This is a double displacement reaction.

2. Copper(II) Chloride - Potassium hydroxide will react with copper(II) chloride to form copper(II) hydroxide and potassium chloride. - The balanced chemical equation for this reaction is: ``` 2KOH + CuCl2 → Cu(OH)2 + 2KCl ``` - This is also a double displacement reaction.

3. Magnesium Hydroxide - Potassium hydroxide will not react with magnesium hydroxide as both are already hydroxides and no reaction will occur.

4. Sulfur(VI) Oxide (Sulfur Dioxide) - Potassium hydroxide will react with sulfur dioxide to form potassium sulfite and water. - The balanced chemical equation for this reaction is: ``` 2KOH + SO2 → K2SO3 + H2O ``` - This is a double displacement reaction.

5. Iron(III) Sulfate - Potassium hydroxide will react with iron(III) sulfate to form iron(III) hydroxide and potassium sulfate. - The balanced chemical equation for this reaction is: ``` 2KOH + Fe2(SO4)3 → 2Fe(OH)3 + 3K2SO4 ``` - This is also a double displacement reaction.

Conclusion

Potassium hydroxide will react with aluminum oxide, copper(II) chloride, sulfur dioxide, and iron(III) sulfate, forming different products through double displacement reactions. However, it will not react with magnesium hydroxide as both are already hydroxides.