Question

При обжиге 0,9 кг пирита получено 768 г оксида серы.вычислить выход продукта реакции

Answer 1

4FeS2+11O2->8SO2+2Fe2O3. n(SO2,практ)=m/M=768/64=12моль, n(FeS2)=m/M=900/120=7,5моль=0,5n(SO2,теор), n(SO2,теор)=7,5*2=15моль, w(выхода)=n(SO2,практ)*100%/n(SO2,теор)=12*100.15=80%. Ответ: w(выхода)=80%.

Answer 2

Calculation of Product Yield in the Reaction

To calculate the yield of the reaction, we need to determine the amount of product obtained relative to the amount of reactant used. In this case, we have 0.9 kg of pyrite and 768 g of sulfur oxide (oxide of sulfur) as the product.

To calculate the yield, we can use the following formula:

Yield (%) = (Amount of Product Obtained / Amount of Reactant Used) x 100

Let's calculate the yield using the given values:

Amount of Reactant Used: 0.9 kg of pyrite = 900 g (1 kg = 1000 g)

Amount of Product Obtained: 768 g of sulfur oxide

Yield (%) = (768 g / 900 g) x 100

Now, let's calculate the yield:

Yield (%) = (768 g / 900 g) x 100 = 85.33%

Therefore, the yield of the reaction is approximately 85.33%.

Please note that the calculation assumes that the reaction proceeds to completion and there are no other factors affecting the yield.