Ребят, помогите, пожалуйста, завершить уравнение реакции: CrSO4 + K2Cr2O7 + H2SO4 = K2SO4 +
Cr2(SO4)3 + ...Ответы на вопрос
6CrSO4 + K2Cr2O7 + 7H2SO4 = K2SO4 + 4Cr2(SO4)3 + 7Н2О
Balancing the Chemical Equation
To balance the given chemical equation: CrSO4 + K2Cr2O7 + H2SO4 = K2SO4 + Cr2(SO4)3 + ...
We need to follow these steps:
1. Write down the unbalanced equation. 2. Balance the elements one at a time by adding coefficients. 3. Ensure that the same number of each type of atom is present on both sides of the equation.
Let's proceed with balancing the given chemical equation step by step.
Balancing the Equation Step by Step
The unbalanced chemical equation is: CrSO4 + K2Cr2O7 + H2SO4 = K2SO4 + Cr2(SO4)3 + ...
First, let's balance the elements one by one.
Balancing the Equation for Sulfur (S)
On the left-hand side, we have: - 1 sulfur atom in CrSO4 - 4 sulfur atoms in H2SO4 - Total: 5 sulfur atoms
On the right-hand side, we have: - 1 sulfur atom in K2SO4 - 3 sulfur atoms in Cr2(SO4)3 - Total: 4 sulfur atoms
To balance the sulfur atoms, we can multiply K2SO4 by 4 and Cr2(SO4)3 by 1 to get 4 sulfur atoms on both sides.
The balanced equation for sulfur becomes: CrSO4 + K2Cr2O7 + 4H2SO4 = 4K2SO4 + Cr2(SO4)3 + ...
Balancing the Equation for Chromium (Cr)
On the left-hand side, we have: - 1 chromium atom in CrSO4 - 2 chromium atoms in K2Cr2O7 - 2 chromium atoms in Cr2(SO4)3 - Total: 5 chromium atoms
On the right-hand side, we have: - 2 chromium atoms in K2Cr2O7 - 2 chromium atoms in Cr2(SO4)3 - Total: 4 chromium atoms
To balance the chromium atoms, we can multiply K2Cr2O7 by 2 to get 4 chromium atoms on both sides.
The balanced equation for chromium becomes: CrSO4 + 2K2Cr2O7 + 4H2SO4 = 4K2SO4 + Cr2(SO4)3 + ...
Conclusion
The balanced chemical equation, considering only the elements sulfur and chromium, is: CrSO4 + 2K2Cr2O7 + 4H2SO4 = 4K2SO4 + Cr2(SO4)3 + ...
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