Question

Расставить методом электронного баланса коэфффициенты в реакциях:HNO3(разб) + Cu--->Cu(NO3)2+NO+H2OHNO3(разб) + Al--->Al(NO3)3+N2O+H2Oзаранее спасибо!

Answer 1

8HNO3(разб) + 3Cu = 3Cu(NO3)2 + 2NO + 4H2O

Cu⁰ - 2e = Cu²⁺  3 окисление

N⁺⁵ + 3e = N⁺²   2 восстановление

 

30HNO3(разб) + 8Al = 8Al(NO3)3 + 3N2O + 15H2O

Al⁰ - 3e = Al⁺³   4  окисление

N⁺⁵ + 4e = N⁺¹   3  восстановление

 

 

Answer 2

Balancing Chemical Equations using the Electron Balance Method

To balance the given chemical equations using the electron balance method, we need to ensure that the number of atoms of each element is the same on both sides of the equation. We will start by balancing the atoms that appear in only one compound on each side of the equation, and then proceed to balance the remaining atoms.

Let's balance the given equations step by step:

1. HNO3(разб) + Cu → Cu(NO3)2 + NO + H2O

To balance the equation, we will start by balancing the atoms that appear in only one compound on each side.

- Balancing nitrogen (N): There is one nitrogen atom on the left side and two nitrogen atoms on the right side. To balance the nitrogen atoms, we need to put a coefficient of 2 in front of the product Cu(NO3)2.

The equation now becomes:

HNO3(разб) + Cu → 2Cu(NO3)2 + NO + H2O

- Balancing hydrogen (H): There are three hydrogen atoms on the left side and four hydrogen atoms on the right side. To balance the hydrogen atoms, we need to put a coefficient of 4 in front of the product H2O.

The balanced equation is:

HNO3(разб) + Cu → 2Cu(NO3)2 + NO + 4H2O

2. HNO3(разб) + Al → Al(NO3)3 + N2O + H2O

- Balancing nitrogen (N): There is one nitrogen atom on the left side and three nitrogen atoms on the right side. To balance the nitrogen atoms, we need to put a coefficient of 3 in front of the product Al(NO3)3.

The equation now becomes:

HNO3(разб) + Al → 3Al(NO3)3 + N2O + H2O

- Balancing hydrogen (H): There are three hydrogen atoms on the left side and six hydrogen atoms on the right side. To balance the hydrogen atoms, we need to put a coefficient of 6 in front of the product H2O.

The balanced equation is:

HNO3(разб) + Al → 3Al(NO3)3 + N2O + 6H2O

- Balancing oxygen (O): There are nine oxygen atoms on the right side (3 in Al(NO3)3 and 6 in H2O), but only three oxygen atoms on the left side (in HNO3). To balance the oxygen atoms, we need to put a coefficient of 6 in front of HNO3.

The final balanced equation is:

6HNO3(разб) + Al → 3Al(NO3)3 + N2O + 6H2O

I hope this helps! Let me know if you have any further questions.