Question

1) N2H4+KIO3+KOH= 2) Zn+HN3= Решить методом электронно-ионного метода!))

Answer 1

Здравствуйте!

1) 3 N2H4 + 2 KIO3 + (KOH) = 3 N2 + 2 KI + 6 H2O
восстановитель N2H4(0)   +  4OH(-) +4электрона = N2(0) + 4H2O, окисление |3
окислитель IO3(-)   +  3H2O     -6электронов =    I(-) + 6OH(-) , восстановление |2
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3 N2H4(0) + 2 IO3(-)  + 12 OH(-) + 6H2O = 3 N2(0) + 12 OH(-) + 2 I(-) +  12H2O
3 N2H4(0) + 2 IO3(-)  = 3 N2(0) + 2 I(-) +  6 H2O
12OH- СОКРАЩАЮТСЯ, KOH не нужно писать до стрелки, различными способами пробовала уже

2) Zn + 3 HN3 = Zn(N3)2 + N2 + NH3
восстановитель Zn(0)    +2электрона = Zn(2+) , окисление |1
окислитель N3(-)     +   3H(+)    -2электрона =    N2(0) +NH3(0) , восстановление |1
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 Zn(0) + N3(-)     +3H(+) = Zn(2+)  + N2(0) +NH3(0)

Answer 2

Electrochemical Method for Balancing Equations

To balance the given chemical equations using the electrochemical method, we need to follow a step-by-step process. Let's go through each equation one by one.

Equation 1: N2H4 + KIO3 + KOH

To balance this equation, we need to assign oxidation numbers to each element and identify the species being oxidized and reduced. Then, we can balance the equation by adding electrons and balancing the charges.

The balanced equation is as follows: N2H4 + KIO3 + KOH → N2 + IO3- + K+ + H2O

Equation 2: Zn + HN3

To balance this equation, we need to assign oxidation numbers to each element and identify the species being oxidized and reduced. Then, we can balance the equation by adding electrons and balancing the charges.

The balanced equation is as follows: Zn + HN3 → Zn(N3)2 + NH3

Please note that the given equation contains HN3, which is hydrazoic acid. Hydrazoic acid is a highly explosive and toxic compound, so it should be handled with extreme caution.

I hope this helps! Let me know if you have any further questions.