Question

Напишите пожалуйста дано. Сожгли 4,7 г фенола и получившийся оксид углерода (IV) пропустили через раствор гидроксида кальция, взятого в избытке. Сколько граммов карбоната кальция образовалось?

Answer 1

Образовалось 7,4г карбоната

Answer 2

Calculation of Calcium Carbonate Formation

To calculate the amount of calcium carbonate formed when 4.7 g of phenol is burned and the resulting carbon dioxide is passed through an excess solution of calcium hydroxide, we need to consider the stoichiometry of the reaction.

The balanced chemical equation for the reaction between carbon dioxide and calcium hydroxide is:

CO2 + Ca(OH)2 → CaCO3 + H2O

From the balanced equation, we can see that one mole of carbon dioxide reacts with one mole of calcium hydroxide to produce one mole of calcium carbonate.

To determine the amount of calcium carbonate formed, we need to convert the mass of phenol burned to moles of carbon dioxide using the molar mass of phenol and the molar mass of carbon dioxide.

The molar mass of phenol (C6H6O) is approximately 94.11 g/mol, and the molar mass of carbon dioxide (CO2) is approximately 44.01 g/mol.

Let's calculate the number of moles of carbon dioxide produced:

moles of CO2 = mass of phenol / molar mass of phenol

moles of CO2 = 4.7 g / 94.11 g/mol

Using the given mass of phenol, we can calculate the moles of carbon dioxide produced.

Now, since the reaction occurs in excess calcium hydroxide, all the carbon dioxide will react to form calcium carbonate. Therefore, the moles of calcium carbonate formed will be equal to the moles of carbon dioxide produced.

Finally, we can calculate the mass of calcium carbonate formed using the moles of calcium carbonate and the molar mass of calcium carbonate.

The molar mass of calcium carbonate (CaCO3) is approximately 100.09 g/mol.

Let's calculate the mass of calcium carbonate formed:

mass of CaCO3 = moles of CaCO3 * molar mass of CaCO3

Now, let's perform the calculations:

moles of CO2 = 4.7 g / 94.11 g/mol = 0.0499 mol

mass of CaCO3 = 0.0499 mol * 100.09 g/mol = 4.99 g

Therefore, approximately 4.99 grams of calcium carbonate will be formed when 4.7 grams of phenol is burned and the resulting carbon dioxide is passed through an excess solution of calcium hydroxide.