Question

1)CUSO4+NAOH= 2)CACL2+K3PO4= 3)AE2(SO4)3+BA(NO3)2= 4)NA2SO3+4CL= 5)NA2CO3+HCL=

Answer 1

1) CuSO4 + 2 NaOH = Cu (OH)2 + Na2SO4
2)2K3PO4+3CaCl2=6KCl+Ca3(PO4)2
5)2HCL+Na2CO3=H2CO3+2NaCL
остальное не знаю, прости

Answer 2

Смотрите фото в вложении

Answer 3

1) CUSO4 + NAOH =

When copper(II) sulfate (CUSO4) reacts with sodium hydroxide (NaOH), a double displacement reaction occurs. The products of this reaction are copper(II) hydroxide (Cu(OH)2) and sodium sulfate (Na2SO4) [[1]].

2) CACL2 + K3PO4 =

When calcium chloride (CaCl2) reacts with potassium phosphate (K3PO4), a double displacement reaction occurs. The products of this reaction are calcium phosphate (Ca3(PO4)2) and potassium chloride (KCl) [[2]].

3) AE2(SO4)3 + BA(NO3)2 =

The given equation is not balanced. However, assuming "AE" represents a metal cation and "BA" represents another metal cation, the balanced equation would be:

2AE2(SO4)3 + 3BA(NO3)2 → AE2(SO4)3 + 3BA2(SO4)3

In this reaction, the metal sulfates (AE2(SO4)3) and metal nitrates (BA(NO3)2) exchange ions to form new compounds. The balanced equation shows that two moles of AE2(SO4)3 react with three moles of BA(NO3)2 to produce one mole of AE2(SO4)3 and three moles of BA2(SO4)3 [[3]].

4) NA2SO3 + 4CL =

When sodium sulfite (Na2SO3) reacts with chlorine (Cl2), a redox reaction occurs. The products of this reaction are sodium chloride (NaCl) and sodium chlorate (NaClO3) [[4]].

5) NA2CO3 + HCL =

When sodium carbonate (Na2CO3) reacts with hydrochloric acid (HCl), a double displacement reaction occurs. The products of this reaction are sodium chloride (NaCl) and carbonic acid (H2CO3). However, carbonic acid is unstable and decomposes into water (H2O) and carbon dioxide (CO2) [[5]].

Please note that the equations provided are simplified and may not represent the complete reaction mechanisms.