Question

Найти массу основы, что образовался при взаимодействии с водой и 20 грамм BaO

Answer 1

    20 г                                               Х г
    BaO        +        H2O        ->        Ba(OH)2
n=1 моль                                        n=1 моль
М = 153 г/моль                               М = 171 г/моль
m=153 г                                           m=171 г

20 г ВаО    -    Х г Ва(ОН)2
153 г ВаО   -   171 г Ва(ОН)2
m(Ba(OH)2) = 20 * 171 / 153 = 22,35 г

Answer 2

Finding the Molar Mass of Ba(OH)2

To find the molar mass of the compound formed by the interaction with water and 20 grams of BaO, we can use the chemical equation for the reaction between BaO and water. The reaction is as follows:

BaO + H2O → Ba(OH)2

The molar mass of BaO is 153.32 g/mol, and the molar mass of water (H2O) is 18.015 g/mol. From this, we can calculate the molar mass of Ba(OH)2.

Using the molar masses of BaO and H2O, we can calculate the molar mass of Ba(OH)2 as follows:

Molar mass of Ba(OH)2 = Molar mass of BaO + 2 * Molar mass of H2O

Molar mass of Ba(OH)2 = 153.32 g/mol + 2 * 18.015 g/mol Molar mass of Ba(OH)2 = 189.35 g/mol

Therefore, the molar mass of the compound formed by the interaction with water and 20 grams of BaO is 189.35 g/mol.

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