Question

Сколько граммов оксида кальция (CaO) получится при разложении 200г CaCO3 CaCO3=CaO+CO2?

Answer 1

CaCO3=CaO+CO2
1 моль---1 моль
n(CaCO3)=200/100=2 моль=n(CaO)
Mr(CaCO3)=100
Mr(CaO)=56
m(CaO)=2*56=112 г

Answer 2

Calculating the Amount of Calcium Oxide (CaO) Produced

To calculate the amount of calcium oxide (CaO) produced when 200g of calcium carbonate (CaCO3) decomposes into CaO and CO2, we can use stoichiometry to find the molar ratio between CaCO3 and CaO.

The balanced chemical equation for the decomposition of CaCO3 is: CaCO3 → CaO + CO2

According to the stoichiometry of the reaction, 1 mole of CaCO3 produces 1 mole of CaO. The molar mass of CaCO3 is 100.09 g/mol, and the molar mass of CaO is 56.08 g/mol.

Using this information, we can calculate the amount of CaO produced.

Calculation

1. Calculate the moles of CaCO3: - Moles = Mass / Molar mass - Moles = 200g / 100.09 g/mol - Moles ≈ 1.999 moles

2. Since the molar ratio between CaCO3 and CaO is 1:1, the moles of CaO produced will be the same as the moles of CaCO3.

3. Calculate the mass of CaO produced: - Mass = Moles × Molar mass - Mass = 1.999 moles × 56.08 g/mol - Mass ≈ 112.47g

Therefore, approximately 112.47 grams of calcium oxide (CaO) will be produced when 200 grams of calcium carbonate (CaCO3) decomposes.

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