Question

Расставьте степени окисления пожалуйста:CL2; HCLO3; KCLO2; NaCLO4; CaCL2

Answer 1

CL2-  (0)
HCLO3-  h+,cl+5,o(-2)
kCLO2; k+,o(-2),cl+3
 NaCLO4; na+, o(-2), cl+7
 CaCL2; ca+2  ,cl(-)  

Answer 2

Oxidation States of Given Compounds

Cl2: - The oxidation state of Cl in Cl2 is 0. - Chlorine exists as diatomic molecules, and each chlorine atom shares an equal number of electrons, resulting in an oxidation state of 0.

HClO3: - The oxidation states in HClO3 are: H: +1, Cl: +5, O: -2. - The sum of the oxidation states in a neutral compound is 0, so the oxidation state of O is calculated as follows: 1 + 5 + (3 * (-2)) = 0.

KClO2: - The oxidation states in KClO2 are: K: +1, Cl: +3, O: -2. - The sum of the oxidation states in a neutral compound is 0, so the oxidation state of Cl is calculated as follows: 1 + 3 + (2 * (-2)) = 0.

NaClO4: - The oxidation states in NaClO4 are: Na: +1, Cl: +7, O: -2. - The sum of the oxidation states in a neutral compound is 0, so the oxidation state of Na is calculated as follows: 1 + 7 + (4 * (-2)) = 0.

CaCl2: - The oxidation states in CaCl2 are: Ca: +2, Cl: -1. - The sum of the oxidation states in a neutral compound is 0, so the oxidation state of Ca is calculated as follows: 2 + (2 * (-1)) = 0.