Question

Какой объем кислорода потребуется для полного сгорания серы массой 3.8 г

Answer 1

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Answer 2

Calculating Oxygen Required for Complete Combustion of Sulfur

To calculate the amount of oxygen required for the complete combustion of sulfur, we can use the balanced chemical equation for the reaction. The balanced chemical equation for the combustion of sulfur is as follows:

Sulfur (S) + Oxygen (O2) → Sulfur Dioxide (SO2)

From the balanced chemical equation, we can see that 1 mole of sulfur reacts with 1 mole of oxygen to produce 1 mole of sulfur dioxide. The molar mass of sulfur is 32.06 g/mol, and the molar mass of oxygen is 16.00 g/mol.

Calculation

Given that the mass of sulfur is 3.8 g, we can calculate the amount of oxygen required using the following steps:

1. Convert the mass of sulfur to moles using the molar mass of sulfur. 2. Use the mole ratio from the balanced chemical equation to find the moles of oxygen required. 3. Convert the moles of oxygen to grams.

Solution

1. Convert mass of sulfur to moles: - Molar mass of sulfur (S) = 32.06 g/mol - Moles of sulfur = Mass of sulfur / Molar mass of sulfur - Moles of sulfur = 3.8 g / 32.06 g/mol - Moles of sulfur ≈ 0.1186 moles

2. Use mole ratio to find moles of oxygen: - From the balanced chemical equation, the mole ratio of sulfur to oxygen is 1:1. - Moles of oxygen required = Moles of sulfur ≈ 0.1186 moles

3. Convert moles of oxygen to grams: - Mass of oxygen = Moles of oxygen * Molar mass of oxygen - Mass of oxygen = 0.1186 moles * 16.00 g/mol - Mass of oxygen ≈ 1.8976 g

Answer

The amount of oxygen required for the complete combustion of sulfur with a mass of 3.8 g is approximately 1.8976 grams.