Question

Серная кислота массой 9.8 г прореагировала с оксидом кальция.Какова масса полученной соли?

Answer 1

Решение задачи находится на фото

Answer 2

Calculating the Mass of the Produced Salt

To calculate the mass of the salt produced when sulfuric acid reacts with calcium oxide, we can use the balanced chemical equation for the reaction and the given mass of sulfuric acid.

The balanced chemical equation for the reaction between sulfuric acid (H2SO4) and calcium oxide (CaO) is as follows: H2SO4 + CaO → CaSO4 + H2O

From the equation, we can see that one mole of sulfuric acid reacts with one mole of calcium oxide to produce one mole of calcium sulfate and one mole of water.

Given: - Mass of sulfuric acid (H2SO4) = 9.8 g

To find the mass of the produced salt (calcium sulfate, CaSO4), we need to calculate the amount of calcium sulfate produced from the given mass of sulfuric acid.

Calculation Steps

1. Calculate the number of moles of sulfuric acid using its molar mass. 2. Use the mole ratio from the balanced chemical equation to find the moles of calcium sulfate produced. 3. Convert the moles of calcium sulfate to grams to find the mass of the produced salt.

Calculation

1. Calculate the moles of sulfuric acid: - Molar mass of sulfuric acid (H2SO4) = 98.08 g/mol - Moles of H2SO4 = Mass of H2SO4 / Molar mass of H2SO4 - Moles of H2SO4 = 9.8 g / 98.08 g/mol - Moles of H2SO4 ≈ 0.1 mol

2. Use the mole ratio to find the moles of calcium sulfate produced: - From the balanced chemical equation, the mole ratio of H2SO4 to CaSO4 is 1:1. - Moles of CaSO4 produced = Moles of H2SO4 = 0.1 mol

3. Convert moles of calcium sulfate to grams: - Mass of CaSO4 = Moles of CaSO4 × Molar mass of CaSO4 - Molar mass of CaSO4 = 136.14 g/mol - Mass of CaSO4 = 0.1 mol × 136.14 g/mol - Mass of CaSO4 = 13.614 g

Answer

The mass of the produced salt (calcium sulfate) is approximately 13.614 grams.