Question

Сколько литров оксида углерода (IV) (н.у) можно получить при прокаливании известняка CaCO3,массой 80г,содержащего 20% примесей?Помогите пожалуйста

Answer 1

CaCO3  =t°=> CaO + CO2
масса смеси(CaCO3)= 80 г
w(CaCO3)= 0.8
масса в= 0.8 * 8 = 64 г
Ню(CaCO3)= 64 : (40+12+3*16)=0.64 моль - ню(СО2)
V(CO2)= 0,64 * 22/4= 14.336 литров

Answer 2

Calculating the Amount of Carbon Dioxide (IV) Produced from the Thermal Decomposition of Limestone (CaCO3)

To calculate the amount of carbon dioxide (IV) produced from the thermal decomposition of limestone (CaCO3), we can use the following steps:

1. Calculate the moles of CaCO3: - The molar mass of CaCO3 is 100.09 g/mol. - Given the mass of CaCO3 as 80g, we can calculate the moles of CaCO3 using the formula: ``` moles = mass / molar mass ```

The moles of CaCO3 can be calculated as follows: ``` moles = 80g / 100.09 g/mol ```

The result will give us the moles of CaCO3.

2. Determine the Stoichiometry of the Reaction: - The thermal decomposition of CaCO3 can be represented by the following balanced chemical equation: ``` CaCO3(s) -> CaO(s) + CO2(g) ```

3. Calculate the moles of CO2 produced: - From the balanced chemical equation, we can see that 1 mole of CaCO3 produces 1 mole of CO2. - Therefore, the moles of CO2 produced will be the same as the moles of CaCO3.

4. Convert moles of CO2 to liters at standard conditions: - At standard temperature and pressure (STP), 1 mole of any gas occupies 22.4 liters. - We can use this conversion factor to calculate the volume of CO2 produced in liters.

Calculation Steps

1. Calculate the moles of CaCO3: - Moles of CaCO3 = 80g / 100.09 g/mol - Moles of CaCO3 = 0.799 moles

2. Determine the moles of CO2 produced: - Moles of CO2 = Moles of CaCO3 = 0.799 moles

3. Convert moles of CO2 to liters at STP: - Volume of CO2 = Moles of CO2 * 22.4 L/mol

Result

The volume of carbon dioxide (IV) produced from the thermal decomposition of 80g of limestone (CaCO3) is approximately 17.9 liters at standard conditions.