Question

1.Подбери коэффициенты, напишите полные и сокращенные ионно- молекулярные уравнения следующих реакций:а) MgSO4+ K3PO4--> Mg3(PO4)2+ K2SO4б) K2CO3+ HCL--> kCL+ H2O+ CO2 Заранее огромное спасибо!!!)))***

Answer 1

б) K2CO3+2HCl(разб.)=2KCl+CO2+H2O

Ионная реакция:

Полная форма: 2K(+)+CO3(2-)+2H(+)+2Cl=2K(+)+2Cl+CO2+H2O

Краткая форма:  CO3(2-)+2H(+)=CO2+H2O

Answer 2

коэффициенты:

а) 3213

б) 12211

уравнения:

а)3Mg+2PO4=Mg3(PO4)2

б)CO3+2H=H2O+CO2

Answer 3

Reaction 1: MgSO4 + K3PO4 -> Mg3(PO4)2 + K2SO4

To balance the equation and write the complete and net ionic equations, we need to ensure that the number of atoms of each element is the same on both sides of the equation.

The balanced equation for the reaction is as follows:

MgSO4 + K3PO4 -> Mg3(PO4)2 + K2SO4

To write the complete ionic equation, we need to break down all the soluble ionic compounds into their respective ions:

Mg2+(aq) + SO4^2-(aq) + 3K+(aq) + PO4^3-(aq) -> Mg3(PO4)2(s) + 2K+(aq) + SO4^2-(aq)

Now, let's write the net ionic equation by removing the spectator ions (ions that appear on both sides of the equation and do not participate in the reaction):

Mg2+(aq) + PO4^3-(aq) -> Mg3(PO4)2(s)

Reaction 2: K2CO3 + HCl -> KCl + H2O + CO2

To balance the equation and write the complete and net ionic equations, we need to ensure that the number of atoms of each element is the same on both sides of the equation.

The balanced equation for the reaction is as follows:

K2CO3 + 2HCl -> 2KCl + H2O + CO2

To write the complete ionic equation, we need to break down all the soluble ionic compounds into their respective ions:

2K+(aq) + CO3^2-(aq) + 2H+(aq) + 2Cl-(aq) -> 2K+(aq) + 2Cl-(aq) + H2O(l) + CO2(g)

Now, let's write the net ionic equation by removing the spectator ions:

CO3^2-(aq) + 2H+(aq) -> H2O(l) + CO2(g)

Please note that the state of matter for each substance is indicated in parentheses (s for solid, aq for aqueous, l for liquid, and g for gas).