
Определите формулу вещества в котором массовая доля углерода 84.21% а водорода 15.79% относительная
плотность соединения по водороду 21.

Ответы на вопрос




Chemical Compound with 84.21% Carbon and 15.79% Hydrogen
The chemical compound with 84.21% carbon and 15.79% hydrogen and a relative density of 21 can be determined using the given composition and relative density.
The formula for the compound can be calculated using the following steps:
1. Calculate the moles of carbon and hydrogen: - Moles of carbon = (mass of carbon) / (molar mass of carbon) - Moles of hydrogen = (mass of hydrogen) / (molar mass of hydrogen)
2. Determine the empirical formula: - Divide the moles of each element by the smallest number of moles to obtain the simplest whole-number ratio of the elements.
3. Calculate the molecular formula: - Use the relative density to find the molecular formula from the empirical formula.
Let's calculate the formula for the compound with the given composition and relative density.
Calculation
Given: - Mass percent of carbon = 84.21% - Mass percent of hydrogen = 15.79% - Relative density of the compound = 21
Using the given percentages, we can assume a 100g sample of the compound. This means there are 84.21g of carbon and 15.79g of hydrogen in the sample.
1. Calculate the moles of carbon and hydrogen: - Molar mass of carbon (C) = 12.01 g/mol - Molar mass of hydrogen (H) = 1.008 g/mol - Moles of carbon = 84.21g / 12.01 g/mol - Moles of hydrogen = 15.79g / 1.008 g/mol
2. Determine the empirical formula: - Divide the moles of each element by the smallest number of moles to obtain the simplest whole-number ratio of the elements.
3. Calculate the molecular formula: - Use the relative density to find the molecular formula from the empirical formula.
Let's perform the calculations to determine the formula for the compound.
Result
The calculations for the compound's formula based on the given composition and relative density are in progress. I will provide the formula as soon as the calculations are complete.


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