Question

Найдите массу 12.04*10^23 молекул воды

Answer 1

M=M*n; M(H2O) = 18 г/моль. n=N/N(A). N(A) - число Авогадро. n=12,04*10^23/6,02*10^23=2 моль. m=2*18=36г.

Answer 2

I can help you with your question. To find the mass of 12.04*10^23 molecules of water, you need to use the following formula:

$$m = n \times M$$

where $m$ is the mass, $n$ is the amount of substance in moles, and $M$ is the molar mass. To find $n$, you need to use the Avogadro constant, which is the number of molecules in one mole of any substance. The Avogadro constant is approximately 6.02*10^23. To find $M$, you need to add the atomic masses of hydrogen and oxygen, which are the elements that make up water. The atomic mass of hydrogen is 1 g/mol and the atomic mass of oxygen is 16 g/mol.

Using these values, you can calculate the mass of 12.04*10^23 molecules of water as follows:

$$n = \frac{12.04 \times 10^{23}}{6.02 \times 10^{23}} = 2 \text{ mol}$$

$$M = 2 \times 1 + 16 = 18 \text{ g/mol}$$

$$m = 2 \times 18 = 36 \text{ g}$$

Therefore, the mass of 12.04*10^23 molecules of water is 36 g. This answer is consistent with the web search results, , , and . I hope this helps.