Question

Вследствии взаимодействия метана CH4 массой 8 г с кислородом массой 32 г образовался углекислый газ массой 22 г . Сложите уравнение этой реакции . Посчитайте , какая масса воды образовалась в результате реакции . Пожалуйста . ничего не помню :(

Answer 1

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Answer 2

Balancing the Chemical Equation

To balance the chemical equation for the reaction between methane (CH4) and oxygen (O2) to form carbon dioxide (CO2) and water (H2O), we can follow these steps:

1. Write the unbalanced equation: CH4 + O2 -> CO2 + H2O

2. Count the atoms of each element on both sides of the equation: - Carbon (C): 1 on the left, 1 on the right - Hydrogen (H): 4 on the left, 2 on the right - Oxygen (O): 2 on the left, 2 on the right

3. Balance the equation by adjusting the coefficients: CH4 + 2O2 -> CO2 + 2H2O

So, the balanced chemical equation for the reaction is: CH4 + 2O2 -> CO2 + 2H2O

Calculation of Water Mass Produced

Now, let's calculate the mass of water produced in the reaction.

The molar mass of water (H2O) is 18 g/mol. From the balanced equation, we can see that 1 mole of methane reacts with 2 moles of oxygen to produce 2 moles of water.

Given: - Mass of methane (CH4) = 8 g - Mass of oxygen (O2) = 32 g

We can use the concept of stoichiometry to find the mass of water produced.

1. Calculate the moles of methane and oxygen: Moles of CH4 = Mass of CH4 / Molar mass of CH4 = 8 g / 16 g/mol (molar mass of CH4) = 0.5 moles

Moles of O2 = Mass of O2 / Molar mass of O2 = 32 g / 32 g/mol (molar mass of O2) = 1 mole

2. Determine the limiting reactant: The balanced equation shows that 1 mole of CH4 reacts with 2 moles of O2. Since we have 0.5 moles of CH4 and 1 mole of O2, O2 is in excess.

3. Calculate the moles of water produced: Moles of H2O = Moles of CH4 (since it's the limiting reactant) * 2 = 0.5 moles * 2 = 1 mole

4. Calculate the mass of water produced: Mass of H2O = Moles of H2O * Molar mass of H2O = 1 mole * 18 g/mol = 18 g

Therefore, the mass of water produced in the reaction is 18 grams.

Summary

The balanced chemical equation for the reaction between methane and oxygen to form carbon dioxide and water is: CH4 + 2O2 -> CO2 + 2H2O

The mass of water produced in the reaction is 18 grams.