Question

Реакции щелочного гидролиза 5,6 г смеси этилового эфиров уксусной и муравьиной кислоты потратили 25,93 мл раствора гидроксида натрия с массой долей щелочи 10% и плотностью 1,08 г / мл.Визначте массовые доли эфиров в исходной смеси.

Answer 1

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Answer 2

Reaction of Alkaline Hydrolysis of Ethyl Ether Mixture

To determine the mass fractions of the ethers in the initial mixture, we need to analyze the reaction of alkaline hydrolysis of the mixture of ethyl acetate and formic acid. The reaction can be represented as follows:

Ethyl acetate + Sodium hydroxide → Sodium acetate + Ethanol

Formic acid + Sodium hydroxide → Sodium formate + Water

The balanced chemical equation for the reaction is:

CH3COOC2H5 + NaOH → CH3COONa + C2H5OH

HCOOH + NaOH → HCOONa + H2O

Now, let's calculate the mass fractions of the ethers in the initial mixture.

Given: - Mass of the mixture = 5.6 g - Volume of sodium hydroxide solution used = 25.93 mL - Concentration of sodium hydroxide solution = 10% - Density of sodium hydroxide solution = 1.08 g/mL

To calculate the mass of sodium hydroxide used, we can use the following formula:

Mass of sodium hydroxide = Volume of sodium hydroxide solution × Density of sodium hydroxide solution

Mass of sodium hydroxide = 25.93 mL × 1.08 g/mL

Now, let's calculate the mass of sodium hydroxide used:

Mass of sodium hydroxide = 27.99 g

To find the mass of the ethers in the initial mixture, we need to consider the stoichiometry of the reaction. From the balanced chemical equation, we can see that 1 mole of ethyl acetate reacts with 1 mole of sodium hydroxide to produce 1 mole of ethanol. Similarly, 1 mole of formic acid reacts with 1 mole of sodium hydroxide to produce 1 mole of water.

The molar mass of ethyl acetate (CH3COOC2H5) is 88.11 g/mol, and the molar mass of formic acid (HCOOH) is 46.03 g/mol.

Let's calculate the moles of sodium hydroxide used:

Moles of sodium hydroxide = Mass of sodium hydroxide / Molar mass of sodium hydroxide

Moles of sodium hydroxide = 27.99 g / 40.00 g/mol

Now, let's calculate the moles of ethyl acetate and formic acid in the initial mixture:

Moles of ethyl acetate = Moles of sodium hydroxide

Moles of formic acid = Moles of sodium hydroxide

To find the mass fractions of the ethers in the initial mixture, we need to calculate the mass of each ether:

Mass of ethyl acetate = Moles of ethyl acetate × Molar mass of ethyl acetate

Mass of formic acid = Moles of formic acid × Molar mass of formic acid

Finally, we can calculate the mass fractions of the ethers:

Mass fraction of ethyl acetate = Mass of ethyl acetate / Mass of the mixture

Mass fraction of formic acid = Mass of formic acid / Mass of the mixture

Please note that without the specific molar ratios of ethyl acetate and formic acid in the initial mixture, we cannot determine the exact mass fractions of each ether. However, the above calculations provide a general approach to determine the mass fractions based on the stoichiometry of the reaction.

Unfortunately, I couldn't find specific information or formulas related to the reaction of alkaline hydrolysis of ethyl ether mixtures in the search results provided. Therefore, the calculations and explanations provided above are based on general knowledge of chemical reactions and stoichiometry.