Question

1.Какой объём оксида углерода(IV)(н.у.) выделится при сжигании 900г угля, содержащего 20% примесей?

Answer 1

С + O2 = CO2

n(CO2) = n(C) = (900*0,8)/12 = 60 моль; 0.8 - это часть чистого угля

V(CO2) = 60 моль * 22,4 л/моль = 1344 л

Ответ - 1344 л

Answer 2

уравнение реакции: С + O2 = CO2
n (CO2) = (0,8*900)/12 = 60 моль

0,8 - чистого угля
V (CO2) = 60 моль*22,4 л/моль = 1344 л

Answer 3

Calculating the Volume of Carbon Dioxide (IV) Produced

To calculate the volume of carbon dioxide (IV) produced when burning 900g of coal containing 20% impurities, we can use the following steps:

1. Determine the Mass of Pure Carbon in the Coal: - Since the coal contains 20% impurities, the mass of pure carbon in the coal is 80% of 900g. - Calculate the mass of pure carbon: 900g * 0.80 = 720g

2. Convert the Mass of Pure Carbon to Moles: - Use the molar mass of carbon to convert the mass of pure carbon to moles. - The molar mass of carbon is approximately 12 g/mol. - Calculate the moles of pure carbon: 720g / 12 g/mol = 60 moles

3. Determine the Volume of Carbon Dioxide (IV) Produced: - The balanced chemical equation for the combustion of carbon is: C + O2 -> CO2 - According to the stoichiometry of the reaction, 1 mole of carbon produces 1 mole of carbon dioxide. - Calculate the volume of carbon dioxide at standard temperature and pressure (STP), which is 22.4 liters per mole.

Calculation Steps

1. Determine the mass of pure carbon in the coal: 900g * 0.80 = 720g. 2. Convert the mass of pure carbon to moles: 720g / 12 g/mol = 60 moles. 3. Determine the volume of carbon dioxide (IV) produced: 60 moles * 22.4 L/mole = 1344 liters.

The volume of carbon dioxide (IV) produced when burning 900g of coal containing 20% impurities is 1344 liters at standard temperature and pressure (STP).