Question

Задание 1) Поставьте формулы солей: -сульфат бария -бромид натрия -сульфид железа -нитрат серебра -карбонат цинка Задание 2) Вычислите массу и количество вещества оксида углерода (IV) образовавшегося при полном сгорании 36г угля Помогите пожалуйста очень срочно нужно

Answer 1

Знаю только первое, так что прости ( BaSO4 NaBr FeS AgNO3 ZnCO3

Answer 2

Task 1: Formulas of Salts

Here are the formulas for the given salts:

- Sulfate of Barium: BaSO4 [[1]] - Bromide of Sodium: NaBr [[2]] - Sulfide of Iron: FeS [[3]] - Nitrate of Silver: AgNO3 [[4]] - Carbonate of Zinc: ZnCO3 [[5]]

Task 2: Calculation of Mass and Amount of Substance

To calculate the mass and amount of substance of carbon dioxide (CO2) formed during the complete combustion of 36g of carbon (C), we need to use the molar mass and stoichiometry.

The molar mass of carbon (C) is 12.01 g/mol, and the molar mass of carbon dioxide (CO2) is 44.01 g/mol.

To find the amount of substance (in moles) of carbon (C), we divide the given mass by its molar mass:

Amount of substance of carbon (C) = Mass of carbon (C) / Molar mass of carbon (C)

Amount of substance of carbon (C) = 36g / 12.01 g/mol ≈ 2.998 mol

According to the balanced chemical equation for the combustion of carbon (C), the stoichiometric ratio between carbon (C) and carbon dioxide (CO2) is 1:1. This means that for every 1 mole of carbon (C) burned, 1 mole of carbon dioxide (CO2) is produced.

Therefore, the amount of substance of carbon dioxide (CO2) formed is also approximately 2.998 mol.

To calculate the mass of carbon dioxide (CO2) formed, we multiply the amount of substance by its molar mass:

Mass of carbon dioxide (CO2) = Amount of substance of carbon dioxide (CO2) × Molar mass of carbon dioxide (CO2)

Mass of carbon dioxide (CO2) = 2.998 mol × 44.01 g/mol ≈ 131.99 g

Therefore, the mass of carbon dioxide (CO2) formed during the complete combustion of 36g of carbon (C) is approximately 131.99 grams.

I hope this helps! Let me know if you have any further questions.