Question

Расчитайте,какой объем будет занимать при нормальных условиях хлор,если его масса в сжиженном состоянии равна 14,2г ПОМОГИТЕ!!! ДАЮ 30 БАЛЛОВ

Answer 1

Раствор Cl2. Найдем n(Cl2)=14,2 г : 71 г/моль=0,2 моль => V(Cl) при н.у. = 22,4 * 0,2=4,48 л. Ответ: 4,48 л.

Answer 2

Calculating the Volume of Chlorine Gas

To calculate the volume of chlorine gas at normal conditions, we can use the ideal gas law, which states that PV = nRT, where P is the pressure, V is the volume, n is the number of moles of gas, R is the ideal gas constant, and T is the temperature in Kelvin. We can rearrange this equation to solve for V (volume) as V = nRT/P.

Given Information

- Mass of chlorine in its liquid state: 14.2g

Steps to Calculate the Volume

1. Convert the mass of chlorine from grams to moles using the molar mass of chlorine. 2. Use the ideal gas law to calculate the volume of chlorine gas at normal conditions.

Calculation

1. Converting mass to moles: - The molar mass of chlorine (Cl2) is approximately 70.906 g/mol. - Number of moles of chlorine = Mass of chlorine / Molar mass of chlorine - Number of moles of chlorine = 14.2g / 70.906 g/mol - Number of moles of chlorine ≈ 0.2 moles

2. Calculating the volume of chlorine gas at normal conditions: - The ideal gas constant, R, is approximately 0.0821 L·atm/(K·mol). - Assuming normal conditions (standard temperature and pressure), the pressure, P, is approximately 1 atm, and the temperature, T, is approximately 273 K. - Volume of chlorine gas = (Number of moles of chlorine) * (Ideal gas constant) * (Temperature) / (Pressure) - Volume of chlorine gas ≈ (0.2 moles) * (0.0821 L·atm/(K·mol)) * (273 K) / (1 atm) - Volume of chlorine gas ≈ 4.5 L

Conclusion

Under normal conditions, the volume of chlorine gas that would be occupied by 14.2g of chlorine in its liquid state is approximately 4.5 liters.