Question

Етанол + hbr= закінчити рівняння

Answer 1

C2H5OH + HBr ----> C2H5Br + H2O

Answer 2

Equating the Equation: Ethanol + HBr

To balance the equation involving ethanol (C2H5OH) and hydrogen bromide (HBr), we need to ensure that the number of atoms on both sides of the equation is equal.

The unbalanced equation is as follows: ``` C2H5OH + HBr → ? ```

To balance this equation, we need to determine the coefficients that go in front of each compound or element. Let's break down the equation and balance it step by step.

Balancing the Carbon Atoms (C)

On the left side of the equation, we have 2 carbon atoms from ethanol (C2H5OH). On the right side, there is only 1 carbon atom from hydrogen bromide (HBr). To balance the carbon atoms, we need to place a coefficient of 2 in front of HBr.

The equation now looks like this: ``` C2H5OH + 2HBr → ? ```

Balancing the Hydrogen Atoms (H)

On the left side of the equation, we have 6 hydrogen atoms from ethanol (C2H5OH). On the right side, we have 2 hydrogen atoms from hydrogen bromide (HBr). To balance the hydrogen atoms, we need to place a coefficient of 3 in front of ethanol.

The equation now looks like this: ``` 3C2H5OH + 2HBr → ? ```

Balancing the Oxygen Atoms (O)

On the left side of the equation, we have 3 oxygen atoms from ethanol (C2H5OH). On the right side, there are no oxygen atoms. To balance the oxygen atoms, we need to add a product that contains oxygen. In this case, we can add water (H2O) as a product.

The balanced equation is: ``` 3C2H5OH + 2HBr → 2C2H5Br + 3H2O ```

Therefore, the balanced equation for the reaction between ethanol and hydrogen bromide is: ``` 3C2H5OH + 2HBr → 2C2H5Br + 3H2O ```

Please note that this balanced equation represents a hypothetical reaction and may not reflect the actual conditions or products of a real-world reaction.

Answer 3

Рівняння для реакції етанолу (C2H5OH) з соляною кислотою (HBr) виглядає наступним чином:

C2H5OH + HBr → C2H5Br + H2O

У цій реакції етанол реагує з соляною кислотою, утворюючи брометан та воду.