Question

Этилен объемом 200 л (н.у) подвергли гидратации и с выходом 75% получили этанол, массой которого составляла________г. Химики напишите решение и решите задачу умоляю. Распишите подробно!

Answer 1

Оюсжрсжорсжоэпдчрпжрлибсжсосоюдчпжан

Answer 2

Problem Statement

We have 200 liters of ethylene (at standard temperature and pressure) that undergoes hydration, resulting in a 75% yield of ethanol. We need to determine the mass of ethanol produced.

Solution

To solve this problem, we need to calculate the mass of ethanol produced from the given volume of ethylene and the yield percentage.

1. Convert the volume of ethylene from liters to grams using its molar mass. 2. Calculate the molar mass of ethanol. 3. Determine the moles of ethylene using its molar mass and volume. 4. Calculate the moles of ethanol produced using the yield percentage. 5. Convert the moles of ethanol to grams using its molar mass.

Let's go through each step in detail.

Step 1: Convert the volume of ethylene to grams

To convert the volume of ethylene from liters to grams, we need to use its molar mass. The molar mass of ethylene (C2H4) is approximately 28.05 g/mol.

The given volume of ethylene is 200 liters. To convert this to grams, we can use the following conversion factor:

1 liter of ethylene = 28.05 grams

Therefore, the mass of ethylene is:

Mass of ethylene = 200 liters * 28.05 grams/liter = 5610 grams

Step 2: Calculate the molar mass of ethanol

The molar mass of ethanol (C2H5OH) can be calculated by summing the atomic masses of its constituent elements. The atomic masses of carbon (C), hydrogen (H), and oxygen (O) are approximately 12.01 g/mol, 1.01 g/mol, and 16.00 g/mol, respectively.

The molar mass of ethanol is:

Molar mass of ethanol = (2 * atomic mass of carbon) + (6 * atomic mass of hydrogen) + atomic mass of oxygen = (2 * 12.01 g/mol) + (6 * 1.01 g/mol) + 16.00 g/mol = 46.07 g/mol

Step 3: Determine the moles of ethylene

To determine the moles of ethylene, we need to divide the mass of ethylene by its molar mass.

Moles of ethylene = Mass of ethylene / Molar mass of ethylene = 5610 grams / 28.05 g/mol = 200 moles

Step 4: Calculate the moles of ethanol produced

The yield percentage of ethanol is given as 75%. This means that 75% of the moles of ethylene will be converted to moles of ethanol.

Moles of ethanol produced = Moles of ethylene * Yield percentage = 200 moles * 0.75 = 150 moles

Step 5: Convert the moles of ethanol to grams

To convert the moles of ethanol to grams, we need to multiply the moles by its molar mass.

Mass of ethanol produced = Moles of ethanol produced * Molar mass of ethanol = 150 moles * 46.07 g/mol = 6910.5 grams

Therefore, the mass of ethanol produced is approximately 6910.5 grams.

Please note that the calculations provided above are based on the given information and assumptions.