Question

Железную руду массой 6,5 т содержащую 15% оксида железа (3) подвергли восстановлению водородом рассчитали массу железа полученного в этом процессе

Answer 1

Решение на фото --------------

Answer 2

Calculation of Iron Obtained from the Reduction of Iron Ore

To calculate the mass of iron obtained from the reduction of iron ore, we need to consider the mass of the iron ore and the percentage of iron oxide present in it.

Given: - Mass of iron ore: 6.5 t - Percentage of iron oxide (Fe2O3): 15%

To calculate the mass of iron obtained, we can use the following steps:

1. Convert the mass of iron ore from tons to kilograms: - 1 ton = 1000 kg - Therefore, the mass of iron ore is 6.5 t * 1000 kg/t = 6500 kg.

2. Calculate the mass of iron oxide (Fe2O3) in the iron ore: - The percentage of iron oxide is 15%, which means that 15% of the mass of the iron ore is iron oxide. - Mass of iron oxide = 15% * 6500 kg = 0.15 * 6500 kg = 975 kg.

3. Calculate the molar mass of Fe2O3: - The molar mass of Fe2O3 can be calculated by adding the atomic masses of iron (Fe) and oxygen (O). - Molar mass of Fe2O3 = (2 * atomic mass of Fe) + (3 * atomic mass of O) - The atomic mass of Fe is approximately 55.845 g/mol, and the atomic mass of O is approximately 15.999 g/mol. - Molar mass of Fe2O3 = (2 * 55.845 g/mol) + (3 * 15.999 g/mol) = 159.69 g/mol.

4. Calculate the number of moles of Fe2O3: - Number of moles = Mass / Molar mass - Number of moles of Fe2O3 = 975 kg / (159.69 g/mol) = 6.107 mol.

5. Calculate the number of moles of iron (Fe): - In the reaction, each mole of Fe2O3 produces 2 moles of Fe. - Number of moles of Fe = 2 * Number of moles of Fe2O3 = 2 * 6.107 mol = 12.214 mol.

6. Calculate the mass of iron (Fe) obtained: - Mass of iron (Fe) = Number of moles of Fe * Molar mass of Fe - The molar mass of Fe is approximately 55.845 g/mol. - Mass of iron (Fe) = 12.214 mol * 55.845 g/mol = 682.47 g.

Therefore, the mass of iron obtained from the reduction of the iron ore is approximately 682.47 grams.