Question

Фосфид цинка ZN3P2весьма ядовит и используется для борьбы с грызунами.Летальная доза для средней серой крысы составляет 20,56 мг,а для мыши 4,1мг. Какое количество мышей и крыс может погибнуть от 0,16ммоль фосфида цинка

Answer 1

1)M (Zn3P2) = 257 мг/моль
2)m (Zn3P2) = 257 ∙ 0,16 = 41,12 мг
3)41,12/20,56=2  41.12/4,1 = 10
В итоге 2 крысы; 10 мышей.

Answer 2

Zinc Phosphide (Zn3P2) and its Toxicity

Zinc phosphide (Zn3P2) is a highly toxic compound that is commonly used for rodent control. It is known for its effectiveness in eliminating rodents such as rats and mice. The lethal dose of zinc phosphide varies depending on the species of rodent.

According to the information provided, the lethal dose of zinc phosphide for an average-sized gray rat is 20.56 mg, while for a mouse, it is 4.1 mg.

Calculating the Number of Mice and Rats Affected

To determine the number of mice and rats that could be affected by a given amount of zinc phosphide, we need to convert the given quantity of zinc phosphide (0.16 mmol) into milligrams.

The molar mass of zinc phosphide (Zn3P2) is approximately 258.09 g/mol. To convert millimoles (mmol) to milligrams (mg), we can use the molar mass:

0.16 mmol * 258.09 mg/mol = 41.29 mg

Therefore, we have 41.29 mg of zinc phosphide.

To calculate the number of mice and rats that could be affected, we can use the lethal dose values provided:

- For mice: 41.29 mg / 4.1 mg (lethal dose for a mouse) = 10 mice - For rats: 41.29 mg / 20.56 mg (lethal dose for a rat) = 2 rats

Therefore, approximately 10 mice and 2 rats could be affected by 0.16 mmol of zinc phosphide.

Please note that these calculations are based on the information provided and may vary depending on factors such as the size and weight of the rodents, as well as their individual sensitivity to the toxin.