Question

Через раствор натрий гидроксида массой 50г с массовой долей щелочи 0,2 пропустили углекислый газ объемом 2,24дм3(н.у.).Какова масса соли в образовавшемся растворе?

Answer 1

2NaOH+CO2=Na2CO3 + H2O
n(NaOH)=0.25
n(CO2)=0.1
m(Na2CO3)=0.1*106=10,6

Answer 2

Calculation of the Mass of Salt in the Solution

To calculate the mass of salt formed in the solution, we need to determine the chemical equation for the reaction between sodium hydroxide (NaOH) and carbon dioxide (CO2). The balanced chemical equation for this reaction is:

2 NaOH + CO2 -> Na2CO3 + H2O

From the balanced equation, we can see that 2 moles of NaOH react with 1 mole of CO2 to produce 1 mole of Na2CO3.

To find the moles of CO2 in the given volume, we can use the ideal gas law equation:

PV = nRT

Where: P = pressure (in atm) V = volume (in liters) n = moles of gas R = ideal gas constant (0.0821 L.atm/mol.K) T = temperature (in Kelvin)

Given: Volume of CO2 gas (V) = 2.24 dm^3 = 2.24 L (since 1 dm^3 = 1 L) Pressure (P) = not provided Temperature (T) = not provided

Unfortunately, the pressure and temperature are not provided in the question. These values are necessary to calculate the moles of CO2 gas. Without these values, we cannot determine the moles of CO2 and subsequently the mass of salt formed in the solution.

Please provide the pressure and temperature values so that we can proceed with the calculation.