Question

H2SO4(конц) +Ag=Ag2SO4 +SO2 +H2O Методом электронного баланса подберите коэффициент в уравнениях окислительно - восстановительных реакций H2SO4(конц) +Hl=l2+H2S+H2O

Answer 1

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Answer 2

Balancing the Equation H2SO4(conc) + Ag = Ag2SO4 + SO2 + H2O using the Electron Balance Method

To balance the equation H2SO4(conc) + Ag = Ag2SO4 + SO2 + H2O using the electron balance method, we need to ensure that the number of electrons gained by the oxidizing agent is equal to the number of electrons lost by the reducing agent.

Let's break down the reaction and balance it step by step:

1. Start by balancing the atoms other than hydrogen and oxygen. In this case, we have sulfur (S) and silver (Ag).

The left side of the equation has 1 sulfur atom (S), while the right side has 1 sulfur atom in Ag2SO4. So, the sulfur is already balanced.

The left side has 1 silver atom (Ag), while the right side has 2 silver atoms in Ag2SO4. Therefore, we need to balance the silver atoms by placing a coefficient of 2 in front of Ag on the left side.

The equation now becomes: H2SO4(conc) + 2Ag = Ag2SO4 + SO2 + H2O.

2. Next, balance the hydrogen (H) atoms. The left side has 2 hydrogen atoms in H2SO4, while the right side has 2 hydrogen atoms in H2O. So, the hydrogen atoms are already balanced.

3. Finally, balance the oxygen (O) atoms. The left side has 4 oxygen atoms in H2SO4, while the right side has 4 oxygen atoms in Ag2SO4 and SO2. So, the oxygen atoms are already balanced.

The balanced equation is: H2SO4(conc) + 2Ag = Ag2SO4 + SO2 + H2O.

Now, let's move on to balancing the equation H2SO4(conc) + Hl = l2 + H2S + H2O using the electron balance method.

1. Start by balancing the atoms other than hydrogen and oxygen. In this case, we have sulfur (S) and iodine (I).

The left side of the equation has 1 sulfur atom (S), while the right side has 1 sulfur atom in H2S. So, the sulfur is already balanced.

The left side has 1 iodine atom (I), while the right side has 2 iodine atoms in l2. Therefore, we need to balance the iodine atoms by placing a coefficient of 2 in front of Hl on the left side.

The equation now becomes: H2SO4(conc) + 2Hl = l2 + H2S + H2O.

2. Next, balance the hydrogen (H) atoms. The left side has 4 hydrogen atoms in H2SO4 and 2 hydrogen atoms in 2Hl, while the right side has 4 hydrogen atoms in H2S and 2 hydrogen atoms in H2O. So, the hydrogen atoms are already balanced.

3. Finally, balance the oxygen (O) atoms. The left side has 4 oxygen atoms in H2SO4, while the right side has 2 oxygen atoms in H2O. Therefore, we need to balance the oxygen atoms by placing a coefficient of 2 in front of H2O on the left side.

The balanced equation is: H2SO4(conc) + 2Hl = l2 + H2S + 2H2O.

I hope this helps! Let me know if you have any further questions.