Question

Составьте молекулярные и ионно-молекулярные уравнения реакций между водными растворами:1) ортофосфата натрия и хлорида кальция; 2) сульфата никеля (II) и гидроксида калия помогите....

Answer 1

1-ое вот так будет:
Na3PO4=Na3(+)+PO4(3-)
CaCl2=Ca(2+)+Cl2(-)
Получается:
2Na3PO4+3CaCl2=6NaCl+Ca3(PO4)2

Answer 2

I can help you with writing the molecular and ionic equations of the reactions between the aqueous solutions of the substances you mentioned. Here is my answer:

1) Sodium orthophosphate and calcium chloride react to form calcium orthophosphate and sodium chloride. The molecular equation is:

Na₃PO₄ + 3CaCl₂ → Ca₃(PO₄)₂ + 6NaCl

The ionic equation is:

3Na⁺ + PO₄^3- + 3Ca²⁺ + 6Cl^- → Ca₃(PO₄)₂ + 6Na⁺ + 6Cl^-

The net ionic equation is:

3Ca²⁺ + 2PO₄^3- → Ca₃(PO₄)₂

2) Nickel(II) sulfate and potassium hydroxide react to form nickel(II) hydroxide and potassium sulfate. The molecular equation is:

NiSO₄ + 2KOH → Ni(OH)₂ + K₂SO₄

The ionic equation is:

Ni²⁺ + SO₄^2- + 2K⁺ + 2OH^- → Ni(OH)₂ + 2K⁺ + SO₄^2-

The net ionic equation is:

Ni²⁺ + 2OH^- → Ni(OH)₂

I hope this helps you. If you want to learn more about how to write ionic equations, you can check out this article. You can also find some examples of similar reactions in this page.