Question

Определите массу фосфата натрия,которая выделится при взаимодействии 98 г. H3PO4 с NaOH,если выход продукта составляет 92%.

Answer 1

Решение во вложении......

Answer 2

Calculation of the Mass of Sodium Phosphate

To determine the mass of sodium phosphate (Na3PO4) that will be formed when 98 g of phosphoric acid (H3PO4) reacts with sodium hydroxide (NaOH), we need to consider the balanced chemical equation for the reaction:

2 H3PO4 + 6 NaOH → Na3PO4 + 6 H2O

From the balanced equation, we can see that 2 moles of H3PO4 react with 6 moles of NaOH to produce 1 mole of Na3PO4. To calculate the mass of Na3PO4, we need to convert the given mass of H3PO4 to moles and then use the mole ratio from the balanced equation.

1. Calculate the moles of H3PO4: - The molar mass of H3PO4 is 98 g/mol (1 mole of H3PO4 weighs 98 grams). - Therefore, the number of moles of H3PO4 is 98 g / 98 g/mol = 1 mole.

2. Use the mole ratio from the balanced equation: - From the balanced equation, we know that 2 moles of H3PO4 react to produce 1 mole of Na3PO4. - Therefore, the number of moles of Na3PO4 formed is 1 mole / 2 = 0.5 moles.

3. Calculate the mass of Na3PO4: - The molar mass of Na3PO4 is 164 g/mol (1 mole of Na3PO4 weighs 164 grams). - Therefore, the mass of Na3PO4 formed is 0.5 moles * 164 g/mol = 82 grams.

Therefore, the mass of sodium phosphate (Na3PO4) that will be formed when 98 g of phosphoric acid (H3PO4) reacts with sodium hydroxide (NaOH) is 82 grams.