Question

Оксид углерода (lV) имеет массу 154 г. Рассчитайте объём, который он займет при нормальных условиях. Вычислите относительную плотность оксида углерода (lV) по водороду. Спасибо большое заранее

Answer 1

M=154 (г)

M(CO2)=12+2*16=44 (г/моль)
n=m/M=154/44=3.5 (моль)
V=Vm*n, где Vm - объем газа при н.у. = 22.4 (л/моль)
V=22.4*3.5=78.4 (л)

Answer 2

Calculating the Volume of Carbon Monoxide (IV) at Standard Conditions

To calculate the volume of carbon monoxide (IV) at standard conditions, we can use the ideal gas law equation:

V = (nRT)/P

Where: - V = volume of the gas - n = number of moles of the gas - R = ideal gas constant - T = temperature in Kelvin - P = pressure

First, we need to find the number of moles of carbon monoxide (IV) using its mass and molar mass.

The molar mass of carbon monoxide (IV) is 28.01 g/mol.

Given mass = 154 g, we can calculate the number of moles: n = mass / molar mass

n = 154 g / 28.01 g/mol

n ≈ 5.498 mol

Now, we can calculate the volume using the ideal gas law. At standard conditions, the pressure is 1 atm and the temperature is 273.15 K.

V = (5.498 mol * 0.0821 L*atm/mol*K * 273.15 K) / 1 atm

V ≈ 123.5 L

So, the volume of carbon monoxide (IV) at standard conditions is approximately 123.5 liters.

Calculating the Relative Density of Carbon Monoxide (IV) to Hydrogen

The relative density of a gas to hydrogen can be calculated using the formula:

Relative density = (molar mass of gas) / (molar mass of hydrogen)

The molar mass of hydrogen is 2.016 g/mol.

The molar mass of carbon monoxide (IV) is 28.01 g/mol.

Using the formula: Relative density = 28.01 g/mol / 2.016 g/mol

Relative density ≈ 13.88

So, the relative density of carbon monoxide (IV) to hydrogen is approximately 13.88.