Question

Вычислите массу метиламина, которая может вступить в реакцию с 3,36 л хлороводорода

Answer 1

Ch3nh2+hcl=ch3nh3cl
n(ch3nh3cl)=3,36/22,4=0,15 моль
n(ch3nh2)=n(ch3nh3cl)=0,15
m(ch3nh2)=0,15*31=4,65

Answer 2

Calculating the Mass of Methylamine

To calculate the mass of methylamine that can react with 3.36 L of hydrogen chloride, we can use the balanced chemical equation for the reaction between methylamine and hydrogen chloride. The balanced chemical equation is:

Methylamine (CH3NH2) + Hydrogen Chloride (HCl) → Methylammonium Chloride (CH3NH3Cl)

From the balanced chemical equation, we can see that 1 mole of methylamine reacts with 1 mole of hydrogen chloride to produce 1 mole of methylammonium chloride.

Given that the reaction takes place at standard conditions, we can use the ideal gas law to find the number of moles of hydrogen chloride and then use the stoichiometry of the balanced chemical equation to find the mass of methylamine.

Using the ideal gas law: PV = nRT, where P is the pressure, V is the volume, n is the number of moles, R is the ideal gas constant, and T is the temperature.

Given: Volume (V) = 3.36 L Pressure (P) and Temperature (T) are not provided in the search results.

We can calculate the number of moles of hydrogen chloride using the ideal gas law and then use the stoichiometry of the balanced chemical equation to find the mass of methylamine.

Let's proceed with the calculation.