Question

Определить массу эфира которую можно получить из 40 грамм спирта и 30 грамм уксусной кислоты при w=80

Answer 1

Тррррррррррррррррррррррррррррррррррррррррррррррррррррррррррррррррррррррррррррррррррррррррррризвини не знаю

Answer 2

Calculation of the Mass of Ether Obtained from 40 grams of Alcohol and 30 grams of Acetic Acid

To determine the mass of ether that can be obtained from 40 grams of alcohol and 30 grams of acetic acid, we need to consider the reaction between these two compounds. The reaction between alcohol and acetic acid can produce ether and water.

The balanced chemical equation for the reaction is as follows:

Alcohol + Acetic Acid → Ether + Water

To calculate the mass of ether produced, we need to know the molar masses of alcohol (ethanol), acetic acid, and ether.

The molar mass of ethanol (C2H5OH) is approximately 46.07 grams per mole. The molar mass of acetic acid (CH3COOH) is approximately 60.05 grams per mole. The molar mass of ether (C2H5OC2H5) is approximately 74.12 grams per mole.

Using the molar masses, we can calculate the number of moles of alcohol and acetic acid present in the given masses.

Number of moles of alcohol = Mass of alcohol / Molar mass of alcohol Number of moles of acetic acid = Mass of acetic acid / Molar mass of acetic acid

Substituting the given masses:

Number of moles of alcohol = 40 grams / 46.07 grams per mole Number of moles of acetic acid = 30 grams / 60.05 grams per mole

Now, we need to determine the limiting reactant in the reaction. The limiting reactant is the one that is completely consumed and determines the maximum amount of product that can be formed. To do this, we compare the number of moles of alcohol and acetic acid.

The balanced chemical equation shows that the stoichiometric ratio between alcohol and acetic acid is 1:1. Therefore, the number of moles of alcohol and acetic acid is the same.

Since the number of moles of alcohol and acetic acid is the same, we can use either of them to calculate the mass of ether produced.

Mass of ether = Number of moles of alcohol (or acetic acid) × Molar mass of ether

Substituting the values:

Mass of ether = Number of moles of alcohol × Molar mass of ether Mass of ether = Number of moles of acetic acid × Molar mass of ether

Calculating the mass of ether:

Mass of ether = (40 grams / 46.07 grams per mole) × 74.12 grams per mole Mass of ether = (30 grams / 60.05 grams per mole) × 74.12 grams per mole

Simplifying the equation:

Mass of ether = 32.69 grams Mass of ether = 24.68 grams

Therefore, the mass of ether that can be obtained from 40 grams of alcohol and 30 grams of acetic acid is approximately 32.69 grams or 24.68 grams.