Question

Некоторая реакция, отображаемая равнением 2А+Х+А2Х, протекает в растворе. Исходная концентрация А была = 2 моль/л. Через 5 минут концентрация вещества А составляла 0,04 моль/л. Вычислите среднюю скорость реакции за указанный промежуток времени. Во сколько раз изменится концентрация вещества Х за то же время?

Answer 1

Скорость реакции есть изменение концентрации вещества за единицу времени или V=C2-C1
      t2-t1

V=(2-0,04)/5=0,392Моль/л*мин

Answer 2

Calculation of Average Reaction Rate

To calculate the average reaction rate, we need to determine the change in concentration of substance A over the given time interval.

Given: - Initial concentration of A (A₀) = 2 mol/L - Final concentration of A (Aₜ) = 0.04 mol/L - Time interval (Δt) = 5 minutes

The average reaction rate (R) can be calculated using the formula:

R = (Aₜ - A₀) / Δt

Substituting the given values:

R = (0.04 - 2) / 5

Calculating the average reaction rate:

R = -1.96 / 5

R ≈ -0.392 mol/(L·min)

Therefore, the average reaction rate for the given time interval is approximately -0.392 mol/(L·min).

Change in Concentration of Substance X

To determine the change in concentration of substance X over the same time interval, we need to consider the stoichiometry of the reaction.

The balanced equation for the reaction is: 2A + X → A2X

From the equation, we can see that for every 2 moles of A consumed, 1 mole of X is consumed.

Since the initial concentration of A is 2 mol/L and the final concentration is 0.04 mol/L, the change in concentration of A is:

Δ[A] = Aₜ - A₀ = 0.04 - 2 = -1.96 mol/L

Since the stoichiometry of the reaction is 2A + X → A2X, the change in concentration of X can be calculated using the ratio of the coefficients:

Δ[X] = (1/2) * Δ[A] = (1/2) * (-1.96) = -0.98 mol/L

Therefore, the concentration of substance X will decrease by approximately 0.98 mol/L over the same time interval.

Please note that the negative sign indicates a decrease in concentration.